Question

我有一个包含2列的数据库，这些列是（并且需要）相同类型的客户ID。我正在尝试这样一个SQL查询，它将列出每个客户ID在表中显示的次数。到目前为止，我有以下内容，我需要将每个个人ID添加到一起，因此它只列出一次。 enter image description here

SELECT  TblMatch.CustomerID1, Count(TblMatch.[Match ID]) AS [TotalMatch ID]
FROM TblMatch
GROUP BY TblMatch.CustomerID1
UNION
SELECT TblMatch.CustomerID2, Count(TblMatch.[Match ID]) AS [TotalMatch ID]
FROM TblMatch
GROUP BY TblMatch.CustomerID2;

Answer 1

试试这个：

select ID, count([Match ID]) as [TotalMatch ID] from 
(
SELECT  TblMatch.CustomerID1 as ID, TblMatch.[Match ID]
FROM TblMatch
UNION ALL
SELECT TblMatch.CustomerID2 as ID, TblMatch.[Match ID]
FROM TblMatch
) tmp
group by ID

Answer 2

这样的事情应该有效，你的工会全部聚合：

SELECT
  TblMatch.CustomerID1,
  Count(data.[Match ID]) AS [TotalMatch ID] 
FROM
  (
    TblMatch,
    (
      TblMatch.[Match ID]
    )
  UNION ALL
  SELECT
    TblMatch.CustomerID2,
    (
      TblMatch.[Match ID]
    )
  FROM
    TblMatch
  )
  data 
GROUP BY
  TblMatch.CustomerID1;

Answer 3

您的查询应该是这样的：

SELECT * FROM (
    SELECT  CUSTOMERID1,COUNT(*)
      FROM TBLMATCH
  GROUP BY CUSTOMERID1
 UNION ALL
    SELECT  CUSTOMERID2, COUNT(*)
      FROM TBLMATCH
  GROUP BY CUSTOMERID2
)ORDER BY CUSTOMERID1;

具有group by和sum

3 个答案: