Question

我正在使用laravel 5.4，我有一个品牌表和一个产品表，我的关系是这样的：

class Product extends Model
{
  protected $table = 'products';


  public function brand()
  {
    return $this->belongsTo(Brand::class);
  }
}

和

class Brand extends Model
{

  public function products()
  {
    return $this->hasMany(Product::class);
  }
}

我的迁移：

    Schema::create('brands', function (Blueprint $table) {
        $table->increments('id');
        $table->string('name',15)->unique();
        $table->string('tag',15)->unique();
        $table->mediumInteger('numofads')->unsigned()->default(0);
        $table->timestamps();
    });

＆安培;

    Schema::create('products', function (Blueprint $table) {
        $table->increments('id');
        $table->integer('brand_id')->unsigned();
        $table->foreign('brand_id')->references('id')->on('brands')->onDelete('cascade');
        $table->string('name',15)->unique();
        $table->string('tag',15)->nullable()->unique();
        $table->mediumInteger('numofads')->unsigned()->default(0);
        $table->timestamps();
    });

在我的控制器中，我将采用3个品牌并将其发送到视图中：

public function show()
{
   $brands = Brand::take(3)->get();

   return view('show',compact('brands'));
}

在我看来，我会重复一遍，只展示这样的产品：

@foreach($brands as $brand)
   {{ $brand->products->name }}
@endforeach

我认为一切正常但我会得到错误：

ErrorException in Collection.php line 1543:
Property [name] does not exist on this collection instance. (View: /home/k1/Laravel/carsan/resources/views/welcome.blade.php)

Answer 1

$brand->products将成为Collection。你将不得不迭代它。它不是单一模型，它可能包含许多模型，就像$brands是一组模型一样。

@foreach ($brands as $brand)
    ...
    @foreach ($brand->products as $product)
        ...
    @endforeach
@endforeach

laravel雄辩的关系不起作用

1 个答案: