Question

我想从Jenkins Declarative Pipeline设置构建名称和描述，但无法找到正确的方法。我尝试在管道之后使用环境括号，在代理程序括号中使用节点括号等。我总是遇到语法错误。

我的Jenkins文件的最后一个版本是这样的：

pipeline {  
    stages {
        stage("Build") {
            steps {
                echo "Building application..."
                bat "%ANT_HOME%/bin/ant.bat clean compile"
                currentBuild.name = "MY_VERSION_NUMBER"
                currentBuild.description = "MY_PROJECT MY_VERSION_NUMBER"
            }
        }
        stage("Unit Tests") {
            steps {
                echo "Testing (JUnit)..."
            echo "Testing (pitest)..."
                bat "%ANT_HOME%/bin/ant.bat run-unit-tests"
            }
        }
        stage("Functional Test") {
            steps {
                echo "Selenium..."
            }
        }
        stage("Performance Test") {
            steps {
                echo "JMeter.."
            }
        }
        stage("Quality Analysis") {
            steps {
                echo "Running SonarQube..."
                bat "%ANT_HOME%/bin/ant.bat run-sonarqube-analysis"
            }
        }
        stage("Security Assessment") {
            steps {
                echo "ZAP..."
            }
        }
        stage("Approval") {
            steps {
            echo "Approval by a CS03"
            }
        }
        stage("Deploy") {
            steps {
                echo "Deploying..."
            }
        }
    }
    post {      
        always {
            junit '/test/reports/*.xml'
        }
        failure {
            emailext attachLog: true, body: '', compressLog: true, recipientProviders: [[$class: 'CulpritsRecipientProvider'], [$class: 'DevelopersRecipientProvider']], subject: '[JENKINS] MY_PROJECT build failed', to: '...recipients...'
        }
        success {
            emailext attachLog: false, body: '', compressLog: false, recipientProviders: [[$class: 'DevelopersRecipientProvider']], subject: '[JENKINS] MY_PROJECT build succeeded', to: '...recipients...'
        }
    }       
}

错误是：

org.codehaus.groovy.control.MultipleCompilationErrorsException: startup failed:
WorkflowScript: 11: Expected a step @ line 11, column 5.
                currentBuild.name = "MY_VERSION_NUMBER"
       ^

WorkflowScript: 12: Expected a step @ line 12, column 5.
                currentBuild.description = "MY_PROJECT MY_VERSION_NUMBER"
       ^

理想情况下，我希望能够从build.properties文件或Jenkins构建日志中读取MY_PROJECT和MY_VERSION_NUMBER。关于该要求的任何指导也将受到赞赏。

更新

根据我在下面的答案，以下工作：

stage("Build") {
    steps {
        echo "Building application..."
        bat "%ANT_HOME%/bin/ant.bat clean compile"

        script {
            def props = readProperties  file: 'build.properties'
            currentBuild.displayName = "v" + props['application.version']
        }
    }

现在，通过读取build.properties文件，可以在管道中自动设置构建版本。

Answer 1

我认为这会做你想要的。我能够在script块内完成：

pipeline {
    stages {
        stage("Build"){
            steps {
                script {
                    currentBuild.displayName = "The name."
                    currentBuild.description = "The best description."
                }
                ... do whatever.
            }
        }
    }
}

该脚本是逃离声明性管道的一种逃避方法。可能有一种声明性的方式来做，但我找不到它。还有一点需要注意。我想你想要currentBuild.displayName而不是currentBuild.name在Jenkins全局文件的文档中，我没有在currentBuild下看到name属性。

Answer 2

如果要通过参数为作业设置内部版本名称，可以使用

currentBuild.displayName = "${nameOfYourParameter}"。 确保您使用双引号而不是单引号。

作业配置

使用参数构建作业

构建历史记录

参考：How to set build name in Pipeline job?

Answer 3

Cloudbees对此发表了评论。Cloudbees

从Jenkins声明性管道设置构建名称和描述

3 个答案: