Question

一个从用户那里获取大量数字的程序，当输入q时，它会计算总和最大值和平均值。

class pergunta {
      constructor(perguntas = [], respostas = [], desafios = [], valor = 100, posicao = 0){
        this.perguntas = perguntas;
        this.respostas = respostas;
        this.desafios = desafios;
        this.posicao = posicao;
        this.valor = valor;
        jQuery.ajax({
           url: '../php/consulta.php' + location.search,
           type: "GET",
           dataType: 'json',
           success: function(pergunta, desafio){
               this.perguntas = pergunta.pergunta;
               this.respostas = pergunta.resposta;
               this.desafios = desafio.descricao;

             }
           });

}

    }
    const perguntas = new pergunta();
    console.log(perguntas);

Answer 1

我会使用内置的Python函数：

nums = []

n = input("Please enter a number (or q to quit):")
while n not in {"Q","q","Quit"}:
    nums.append(int(n))
    n = input("Please enter a number (or q to quit):")

print("Count: {}, Max: {}, Min: {}, Sum: {}, Average: {}".format(len(nums),max(nums),min(nums),sum(nums),sum(nums)/len(nums)))

Answer 2

所以这里有3个问题：

您需要使用raw_input代替input。
while n !="q" and "Q" and "Quit":无效，因为它不会n与"q"，"Q"和"Quit"进行比较。它应该是while n !="q" and n != "Q" and n != "Quit":
如果只有一个号码，它将无效。最好将n = input("Please enter another number:")放在while而不是第一行。

试试这个：

n = raw_input("Please enter a number:")
count = 0
min = None
max = 0
sum= 0

while n !="q" and n!="Q" and n!="Quit":
    n1 = float(n)

    if min is None:
        min = n1
    elif n1 < min:
        min = n1

    if n1 > max:
        max = n1

    sum += n1
    count = count +1
    n = raw_input("Please enter another number:")

print("Total:", sum)
print("Count:", count)
print("Min:", min)
print("Max:", max)
print("Average:", sum/count)

数字和计算

2 个答案: