Question

我尝试使用从InputBox传递的文本更新表中的数据。

Private Sub editname_Click()

 Dim GivenNameTB As String
 Dim EnterName As String
 Dim SQl As String
 Dim LocationID As Integer


 Me.txt_name.SetFocus
 GivenNameTB = Me.txt_name.Text
 EnterName = InputBox("Change name", "Change name", GivenNameTB)
 LocationID = Me.list_ma.Column(1)

 SQl = " Update tWorkers SET GivenName = forms!mainform!EnterName WHERE tWorkers.IDName = forms!mainform!LocationID "

 CurrentDb.Execute SQl




End Sub

但是，我收到错误代码3061＆＃34;参数太少。预计2＆＃34;

编辑：

tWorkers 的表结构：

IDName - auto-increment (primary key)
LastName - text
GivenName - text

我按SET GivenName = ...定位列 GivenName ，按位置ID定位行。

LocationID从列表字段 list_ma 中获取其值。列表字段由五列组成，而IDName为第二列。

我的重点是更新表格中的字段。我的表单中的文本框显示一个名称，可以通过单击按钮进行编辑。然后弹出一个输入框。输入的字符串应保存在所需的字段中。

Answer 1

重新阅读您的问题，您的数据存在于VBA变量中，而不是表单控件中。因此，您无法从表单中读取参数（DoCmd.RunSQL无效）。

您必须动态构建SQL字符串，最好使用CSql() by Gustav：

SQL = "Update tWorkers SET GivenName = " & CSql(EnterName) & _
      " WHERE tWorkers.IDName = " & CSql(LocationID)
Debug.Print SQL
CurrentDb.Execute SQL

Answer 2

我认为您需要DoCmd.RunSQL而不是CurrentDb.Execute。

Private Sub editname_Click()

 Dim GivenNameTB As String
 Dim EnterName As String
 Dim SQl As String
 Dim LocationID As Integer

 Me.txt_name.SetFocus
 GivenNameTB = Me.txt_name.Text
 EnterName = InputBox("Change name", "Change name", GivenNameTB)
 LocationID = Me.list_ma.Column(1)

 SQL = " Update tWorkers SET GName = " & chr(34) & EnterName & chr(34) & " WHERE tWorkers.IDName = " & LocationID

 Debug.Print SQL -- For checking what code we are running.

 DoCmd.RunSQL SQL 

End Sub

MS Access - 更新SQL查询错误3061

2 个答案: