SpringBoot找不到处理程序方法

时间:2017-05-02 21:45:04

标签: spring-boot

我有一个基本的SpringBoot应用程序。使用Spring Initializer,嵌入式Tomcat,Thymeleaf模板引擎和包作为可执行的JAR文件。

这是主要的课程

@SpringBootApplication
public class TdkApplication {
    public static void main(String[] args) {
        SpringApplication.run(TdkApplication.class, args);
    }
}

这是一个控制器

@Controller
public class MockupIndexController {
    @RequestMapping("/mockup/index")
    public String welcome(Map<String, Object> model) {
        return "mockups/index";
    }
}

我的pom.xml

 <dependencies>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-actuator</artifactId>
        </dependency>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-web</artifactId>
        </dependency>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-thymeleaf</artifactId>
        </dependency>
        <dependency>
             <groupId>com.tdk.iot.core</groupId>
            <artifactId>tdk-core</artifactId>
            <version>0.0.1-SNAPSHOT</version>
        </dependency>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-test</artifactId>
            <scope>test</scope>
        </dependency>
   </dependencies>

但是当我把它放在网址中时:

http://localhost:8080/mockup/index

我在控制台中获得了以下日志

o.s.web.servlet.DispatcherServlet        : Servlet 'dispatcherServlet' configured successfully
o.s.web.servlet.DispatcherServlet        : DispatcherServlet with name 'dispatcherServlet' processing GET request for [/mockup/index]
s.w.s.m.m.a.RequestMappingHandlerMapping : Looking up handler method for path /mockup/index
s.w.s.m.m.a.RequestMappingHandlerMapping : Did not find handler method for [/mockup/index]
o.s.w.s.handler.SimpleUrlHandlerMapping  : Matching patterns for request [/mockup/index] are [/**]
o.s.w.s.handler.SimpleUrlHandlerMapping  : URI Template variables for request [/mockup/index] are {}
o.s.w.s.handler.SimpleUrlHandlerMapping  : Mapping [/mockup/index] to HandlerExecutionChain with handler [ResourceHttpRequestHandler [locations=[ServletContext resource [/], class path resource [META-INF/resources/], class path resource [resources/], class path resource [static/], class path resource [public/]], resolvers=[org.springframework.web.servlet.resource.PathResourceResolver@8b91134]]] and 1 interceptor
o.s.web.servlet.DispatcherServlet        : Last-Modified value for [/mockup/index] is: -1
o.s.web.servlet.DispatcherServlet        : Null ModelAndView returned to DispatcherServlet with name 'dispatcherServlet': assuming HandlerAdapter completed request handling
o.s.web.servlet.DispatcherServlet        : Successfully completed request
o.s.web.servlet.DispatcherServlet        : DispatcherServlet with name 'dispatcherServlet' processing GET request for [/error]
s.w.s.m.m.a.RequestMappingHandlerMapping : Looking up handler method for path /error

3 个答案:

答案 0 :(得分:10)

我认为在扫描期间找不到您的控制器类,因为它位于默认情况下不会扫描的包中。我想你的应用程序就像com.tdk.app和com.tdk.controller中的控制器一样,对吧?如果是,只需将应用程序移动到com.tdk一级,您的问题就会消失。

答案 1 :(得分:1)

控制器包应该是&#34; TdkApplication&#34;的一级底层包。如果你的&#34; TdkApplication&#34;在com.test包中,然后你的控制器应该在com.test.controller包下。当我们与应用程序包进行比较时,意味着一个级别的包装

答案 2 :(得分:0)

以下工作

应用包应该像com.app

然后控制器将是com.app.controller。

如果你像下面那样使用它,那么spring将无法来扫描控制器

App包:com.app.main

控制器:com.app.controller

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