Question

我有一个玩家及其游戏的数据库。我试图获得一系列游戏，一组给定的玩家有共同点。

示例数据：

PLAYER  GAME
1       A
1       B
1       C
2       B
2       C
3       B
4       A
4       B
5       C
5       B

所以，给定：1, 2, 3, 4它会给我

GAME
B

并给出：1, 2, 5它会给我

GAME
B
C

Answer 1

一种方法是：

with cte as (
    select PLAYER, GAME from your_table where  player in (1, 2, 3, 4)
)
select GAME from cte
group by GAME
having count(distinct PLAYER) = (select count(distinct PLAYER) from cte)

Answer 2

您可以使用条件聚合：

1,2,3,4：

select game
from your_table
group by game
having count(distinct case when player in (1, 2, 3, 4) then player end) = 4;

1,2,5：

select game
from your_table
group by game
having count(distinct case when player in (1, 2, 5) then player end) = 3;

Demo on rextester

Answer 3

只是一个简单的WHERE子句：

SELECT DISTINCT game
FROM table_name
WHERE player in (1, 2, 3, 4);

SELECT DISTINCT game
FROM table_name
WHERE player in (1, 2, 5);

编辑：根据Gurwinder Singh的评论，将DISTINCT关键字添加到查询中。

得到所有共同的行

3 个答案: