尝试使用AJAX发送FormData时表单数据不通过?

时间:2017-05-06 17:46:12

标签: javascript php jquery ajax file-upload

更新

由于 John Conde 建议我,我会尝试更准确地描述我的问题。

main.js 中,我尝试在提交时将表单对象发送到addevent.php。我这样做是通过选择表单对象并创建一个FormData对象并使用AJAX将其发送到addevent.php

$("form[name='add-event-form']").submit(function(e){
        e.preventDefault();
        var title = $(this).find("input[name='title']").val();
        var start_date = $(this).find("input[name='start_date']").val();
        var start_time = $(this).find("input[name='start_time']").val();
        var end_date = $(this).find("input[name='end_date']").val();
        var end_time = $(this).find("input[name='end_time']").val();
        var place = $(this).find("input[name='place']").val();
        var description = $(this).find("input[name='description']").val();
        var file = $(this).find("input[name='file']")[0].files[0];
        var fileData = new FormData();
        fileData.append('file', file);
        var data = {title: title, start_date: start_date, start_time: start_time,
                    end_date: end_date, end_time: end_time, place: place,
                    description: description, file: fileData};
        console.log(data);
        if(title && start_date && start_time){
          var event_form = $.ajax({
            url: 'ajax/addevent.php',
            method: 'POST',
            processData: false,
            contentType: false,
            data: data,
            dataType: 'json',
            error: function (error){
              console.log(error);
            },
            success: function (json){
              console.log(json);
            },
            complete: function (jqXHR, textStatus) {
              console.log(`AJAX thinks login request was a ${textStatus}`);
            }
          });
        }

但是,我知道什么都没有通过b / c我从AJAX调用返回的对象有以下错误: enter image description here

我知道我在data电话中发送的AJAX对象已填写完了b / c我已将其打印出来: enter image description here

很明显,我的data对象由于某种原因没有发送到我的addevent.php。我认为这是processData: false, contentType: false的b / c。我这样做的原因是b / c我正在尝试上传addevent.php中的文件,而this post在我的AJAX调用中表示要processData: false, contentType: false

如果你知道我做错了什么,请告诉我,谢谢!

代码

addevent.php

<?php
session_start();
require_once '../config-db.php';

//Set up SQL
$query = "INSERT INTO events (title, start_date, start_time, end_date, end_time, place, description)
          VALUES (:title, :start_date, :start_time, :end_date, :end_time, :place, :description)";
$fields = array('title', 'start_date', 'start_time', 'end_date', 'end_time', 'place', 'description');
$stmt = $db->prepare($query);

//Set up return
$error['error'] = array();

//N2SELF: N2Do DATA VALIDATION
if(!empty($_FILES['file'])){
  $image=$_FILES['file'];
  $file_name=$_FILES['file']['name'];
  $image_tmp =$_FILES['file']['tmp_name'];
  if($_FILES['file']['error'] === 0){
    $file_path = "images/";
    $move_successfully = move_uploaded_file( $image_tmp, $file_path.$file_name);
    if(!$move_successfully){
      $error['error'][] = "$image_tmp was not moved successfully";
    }
    $_SESSION['photos'][] = $file_name;
    $error['error'][] = "$image_tmp was moved successfully";
  }
}

foreach($fields as $field){
  if($field === 'title' || $field === 'start_date' || $field === 'start_time'){
    if(empty($_POST[$field])){
      $error['error'][] = "No required field: $field";
    }
  }

  if($field === 'title'){
    $value = (!empty($_POST[$field])) ? $_POST[$field] : "Untitled";
  }elseif($field === 'start_date'){
    $value = (!empty($_POST[$field])) ? $_POST[$field] : "NO DATE";
  }
  elseif($field === 'start_time'){
    $value = (!empty($_POST[$field])) ? $_POST[$field] : "NO TIME";
  }else{
    $value = (!empty($_POST[$field])) ? $_POST[$field] : NULL;
  }

  $parameter = ":$field";
  $paramToValues[$parameter] = $value;
}
$executed = $stmt->execute($paramToValues);
if(!$executed){
  $error['error'][] = "SQL query $query not executed";
  echo json_encode($error);
  exit();
}

foreach($fields as $field){
  $error['fields'][] = $_POST[$field];
}
echo json_encode($error);
?>

1 个答案:

答案 0 :(得分:1)

formData使用.submit()中使用this来引用当前表单。

$("form[name='event-form']").submit(function(e){
    e.preventDefault();
    var formData = new FormData(this);
    $.ajax({
        url: 'ajax/addevent.php',
        type: 'POST',
        data: formData,
        dataType: 'json',
        error: function (error) {
            console.log(error);
        },
        contentType: false, // NEEDED, DON'T OMIT THIS (requires jQuery 1.6+)
        processData: false, // NEEDED, DON'T OMIT THIS
        success: function (json) {
            console.log(json);
        },
        complete: function (jqXHR, textStatus) {
            console.log(`AJAX thinks login request was a ${textStatus}`);
        }
    });
});