Question

我有一组文件夹（名为* .pages），我想将其压缩到各自的.zip文件中，例如“example1.pages”进入“example1.pages.zip”，“example2.pages”进入“example2.pages.zip”等。我还想要包含各个.pages文件夹的内容。

目前，该脚本将所有.pages文件压缩为具有嵌套目录的单个文件。

我不知道如何继续，我相信在执行zipfile功能时我会遗漏一些东西。

非常感谢任何帮助！

import os
import zipfile

start_path = "MY/DIRECTORY/HERE"

def zipdir(ziph):
    dir_count = 0
    file_count = 0
    for (path,dirs,files) in os.walk(start_path):
        print('Directory: {:s}'.format(path))
        dir_count += 1

        for file in dirs:
            if file.endswith(".pages"): 
                print('\nAttempting to zip: \'{}\''.format(file))

                ziph.write(os.path.join(path, file))

                print('Done')
                file_count += 1

    print('\nProcessed {} files in {} directories.'.format(file_count,dir_count))    



if __name__ == '__main__':
    zipf = zipfile.ZipFile("NAME/OF/INDIVIDUAL/ZIP/FILE.zip", 'w', zipfile.ZIP_DEFLATED)
    zipdir(zipf)
    zipf.close()

Answer 1

您只需打开一个zip文件并在其中添加所有内容。如果每个文件需要一个zip，则需要在扫描文件时在循环中创建zip文件。

import os
import zipfile

start_path = "MY/DIRECTORY/HERE"
start_path = '.'

def zipdir(start_path):
    dir_count = 0
    file_count = 0
    for (path,dirs,files) in os.walk(start_path):
        print('Directory: {:s}'.format(path))
        dir_count += 1
        for file in files:
            if file.endswith(".pages"): 
                file_path = os.path.join(path, file)
                print('\nAttempting to zip: \'{}\''.format(file_path))
                with zipfile.ZipFile(file_path + '.zip', 'w', zipfile.ZIP_DEFLATED) as ziph:
                    ziph.write(file_path, file)
                print('Done')
                file_count += 1

    print('\nProcessed {} files in {} directories.'.format(file_count,dir_count))

if __name__ == '__main__':
    zipdir(start_path)

Answer 2

您还可以采用@tdelaney的代码并按以下方式使用shutil模块：

enter import os
import shutil

reports_path  = os.getcwd()

def zipdir(reports_path):
for (path,dirs,files) in os.walk(reports_path):

    for d in dirs:
        file_path = os.path.join(path, d)
        print 'Compressing ' + d  
        shutil.make_archive(d,'zip',file_path)
        print "Done"

if __name__ == '__main__':
    zipdir(reports_path)

如何将多个文件夹递归压缩为单独的.zip文件？

2 个答案: