一次一个地生长分形树的分支

Question

我使用Javascript和画布创建分形树。大部分代码来自我观看的视频教程，所以我对它不太熟悉。我控制了一些用滑块确定树的外观的方面。这是javascript：

var angle = 0;
var lengthV = 0;
var multiple = 0;
var branches = 2;
var min = 20;
var sliderA;
var sliderL;
var sliderM;
var sliderm;

function setup() {

    var a = document.createTextNode("Angle");
    document.body.appendChild(a);
    sliderA = createSlider(0,TWO_PI, PI/4, 0.001); //slider to two pi, starts at pi/4, increments of 0.01

    var l = document.createTextNode("Length");
    document.body.appendChild(l);
    sliderL = createSlider(0,500);

    var m = document.createTextNode("Multiple");
    document.body.appendChild(m);
    sliderM = createSlider(0,0.8,0.4,0.01);

    var i = document.createTextNode("Minimum");
    document.body.appendChild(i);
    sliderm = createSlider(1,400,10,1);

    createCanvas(window.innerWidth,window.innerHeight);
}

function draw() {
    background(255); //canvas colour
    angle = sliderA.value();
    lengthV = sliderL.value();
    multiple = sliderM.value();
    min = sliderm.value();
    stroke(0); //line colour
    translate(0.5*window.innerWidth, height) //sets new origin point for branch
    branch(lengthV);
}

function branch(len) {
    line(0, 0, 0, - len); //makes line
    translate(0, -len);
    if (len > min) { //ensure the branch is larger than minimum
        if (branches == 2) {
            push(); //save transformation state
            rotate(angle); //rotate for first branch
            branch(len * multiple); //repeat loop
            pop(); //return back to original transformations state
            push(); //save transformation state
            rotate(-angle); //rotate other way for second branch
            branch(len * multiple);
            pop();
        }
        if (branches == 3) {
            push(); //save transformation state
            rotate(angle); //rotate for first branch
            branch(len * multiple); //grow branch
            pop(); //return back to original transformations state
            push(); //save transformation state
            rotate(0);
            branch(len * multiple); //grow middle branch
            pop(); //return back to original transformations state
            push(); //save transformation state
            rotate(-angle); //rotate other way for third branch
            branch(len * multiple);
            pop();
        }
    }
}

function sleep(ms) {
  return new Promise(resolve => setTimeout(resolve, ms));
}

我有一个递归循环，它取决于branches变量的值，以滑块改变的角度创建一组设定的分支。但是，我想知道是否有一种设置计时器的方法，以便在每个设定的时间段内增加一层分支，而不是一次增长。我对Javascript的了解有限，所以我感谢您给予的任何回复。