获取锚标记HREF和VALUE

时间:2017-05-14 01:26:16

标签: c# regex string parsing find

我有一个看起来像这样的字符串:

<a href="http://forum.tibia.com/forum/?action=board&boardid=476">Amera</a><br><font class="ff_info">This board is for general discussions related to the game world Amera.</font>

如何忽略/删除</a>之后的所有内容,然后只获取网址:http://forum.tibia.com/forum/?action=board&boardid=476和值Amera

所以之后,我想要2个变量及其值,如:

string url = "http://forum.tibia.com/forum/?action=board&boardid=476";

string value = "Amera";

我试过这个来获得价值:

string value = System.Text.RegularExpressions.Regex.Replace(MYSTRING, "(<[a|A][^>]*>|)", "");

但它返回:

Amera</a><br><font class="ff_info">This board is for general discussions related to the game world Amera.</font>

3 个答案:

答案 0 :(得分:0)

要获取网址,请尝试使用此正则表达式模式:/href=\"(.*)\"/

...并获取 > Amera </a> 之间的值 使用类似:>(.+?)</a>

的模式

......虽然,这似乎远非完美......

答案 1 :(得分:0)

如果a标记不包含更多属性,则只能将其用于网址:

\bhref="(.*?)"

对于网址和文字来说更复杂:

<a\b[^>]*?\bhref="([^"]*?)"[^>]*?>(.*?)<\/a>

所以在C#代码中(引号需要转义!):

var html = "<a href=\"http://forum.tibia.com/forum/?action=board&boardid=476\">Amera</a><br><font class=\"ff_info\">This board is for general discussions related to the game world Amera.</font>";
var match = Regex.Match(html, "<a\\b[^>]*?\\bhref=\"([^\"]*?)\"[^>]*?>(.*?)<\\/a>", RegexOptions.IgnoreCase);
if (match.Success) {
    var url = match.Groups[1];
    var text = match.Groups[2]
}

答案 2 :(得分:0)

试试这个:

HtmlDocument dc = new HtmlAgilityPack.HtmlDocument();
        dc.LoadHtml("<a href='http://forum.tibia.com/forum/?action=board&boardid=476'>Amera</a><br><font class='ff_info'>This board is for general discussions related to the game world Amera.</font>");
        foreach (HtmlNode link in dc.DocumentNode.SelectNodes("a"))
        {
            string url = link.Attributes["href"].Value; // http://forum.tibia.com/forum/?action=board&boardid=476
            string value = link.InnerText; // Amera
        }