Question

我有一本字典dict1:{Name:"Alex", 3: "61"}。我创建了一个包含相同键值对的重复字典dict2。我将dict2作为参数发送给一个函数，然后转换为这些值：dict2={1: "Alex",undefined: "61"}。

有人可以帮我编写代码，将undefined:61替换为原始字典中的代码吗？最终的词典必须是：dict={1: "Alex",3: "61"};

dict1={Name:"Alex", 3: "61"};
dict2={Name:"Alex", 3: "61"}; //created a copy of original dictionary
function(dict2){
     //some function that converts dict2 to the following value.
}
console.log(dict2);   //dict2={1: "Alex",undefined: "61"}

//now i want to write the code to substitute the undefined key-value pair to the one present in the original.
//my final dict has to be as follows:
dict={1: "Alex",3: "61"};

Answer 1

获取并存储属性"undefined"，delete "undefined"属性的值;迭代属性，值dict1，如果属性值与存储值匹配，则将dict2处的属性设置为dict1处匹配的属性名称，将存储变量设置为set属性的值。

dict1 = {
  Name: "Alex",
  3: "61"
};

dict2 = {
  1: "Alex",
  undefined: "61"
};

let {undefined:val} = dict2;

delete dict2["undefined"];

for (let [key, prop] of Object.entries(dict1)) {
  if (prop === val) dict2[key] = val;
}

console.log(dict2);

Answer 2

你可以这样做：

迭代第一个对象（dict1）并创建一个新对象，让我们说一下临时键和值的反转。所以临时看起来像{Alex：Name，61：3}。
迭代dict2并在键＃34; undefined＆＃34;，得到值（在这种情况下为61），然后从反转对象中读取值得到3.使用它作为键（3）并放值（61）。
删除密钥＆＃34; undefined＆＃34;来自dict2。

＆＃13;

var dict1 = {
  Name: "Alex",
  3: "61"
};
var dict2 = {
  1: "Alex",
  undefined: "61"
};
var temp = {};
for (var i in dict1) {
  temp[dict1[i]] = i;
}

for (var key in dict2) {
  if (key == "undefined") {
    var val = dict2[key];
    dict2[temp[val]] = val;
  }
}
delete dict2["undefined"];
console.log(dict2);

＆＃13;

如何在JavaScript中从另一个字典的键更改字典的键？

2 个答案: