返回带有错误的响应,而不是在验证管道mediatr 3

时间:2017-05-19 07:34:42

标签: c# asp.net-mvc cqrs mediatr

我目前正在使用Mediatr 3中的Pipeline行为进行请求验证。我遇到的所有示例都抛出ValidationException,如果发生任何故障,而不是这样做,我想返回带有错误的响应。有人知道怎么做吗?

以下是验证管道的代码:

public class ValidationPipeline<TRequest, TResponse> :
    IPipelineBehavior<TRequest, TResponse> where TRequest : IRequest<TResponse>
{
    private readonly IEnumerable<IValidator<TRequest>> _validators;

    public ValidationPipeline(IEnumerable<IValidator<TRequest>> validators)
    {
        _validators = validators;
    }

    public Task<TResponse> Handle(TRequest request, RequestHandlerDelegate<TResponse> next)
    {
        var failures = _validators
            .Select(v => v.Validate(request))
            .SelectMany(result => result.Errors)
            .Where(f => f != null)
            .ToList();

        if (failures.Any())
        {
            throw new ValidationException(failures);
        }

        return next();
    }
}

注意:我发现了这个问题Handling errors/exceptions in a mediator pipeline using CQRS?,我对答案中的第一个选项感兴趣,但没有关于如何做到这一点的明确示例。

这是我的回复课程:

public class ResponseBase : ValidationResult
{
    public ResponseBase() : base() { }

    public ResponseBase(IEnumerable<ValidationFailure> failures) : base(failures)  {
    }
}

我在验证管道类中添加了以下签名:

public class ValidationPipeline<TRequest, TResponse> : IPipelineBehavior<TRequest, TResponse> where TRequest : IRequest<TResponse> 
where TResponse : ResponseBase

我在Handle方法中做到了这一点:

var response = new ResponseBase(failures);
return Task.FromResult<TResponse>(response);

但这给了我错误'无法转换为TResponse'。

3 个答案:

答案 0 :(得分:2)

几年前,我创建了常规的Result对象,并不断进行改进。非常简单,请检查https://github.com/martinbrabec/mbtools

如果可以确定Result(或Result <>)是Application层中的返回类型每种方法,那么您可以使用ValidationBehavior,如下所示:

public class ValidationBehavior<TRequest, TResponse> : IPipelineBehavior<TRequest, TResponse>
    where TRequest : IRequest<TResponse>
    where TResponse : Result, new()
{
    private readonly IEnumerable<IValidator<TRequest>> _validators;

    public ValidationBehavior(IEnumerable<IValidator<TRequest>> validators)
    {
        _validators = validators;
    }

    public Task<TResponse> Handle(TRequest request, CancellationToken cancellationToken, RequestHandlerDelegate<TResponse> next)
    {
        if (_validators.Any())
        {
            var context = new ValidationContext(request);

            List<ValidationFailure> failures = _validators
                .Select(v => v.Validate(context))
                .SelectMany(result => result.Errors)
                .Where(f => f != null)
                .ToList();

            if (failures.Any())
            {
                TResponse response = new TResponse();

                response.Set(ErrorType.NotValid, failures.Select(s => s.ErrorMessage), null);

                return Task.FromResult<TResponse>(response);
            }
            else
            {
                return next();
            }
        }

        return next();
    }

}

由于所有处理程序都返回Result(或基于Result的Result <>),因此您将能够处理所有验证错误而没有任何异常。

答案 1 :(得分:1)

如果发生任何故障,请不要致电next

public Task<TResponse> Handle(TRequest request, RequestHandlerDelegate<TResponse> next)
{
    var failures = _validators
        .Select(v => v.Validate(request))
        .SelectMany(result => result.Errors)
        .Where(f => f != null)
        .ToList();

    if (failures.Any())
    {
        var response = new Thing(); //obviously a type conforming to TResponse
        response.Failures = failures; //I'm making an assumption on the property name here.

        return Task.FromResult(response);
    }
    else
    {
        return next();
    }
}

注意:
您的课程(我的示例中为Thing)必须为TResponse

类型

答案 2 :(得分:0)

您可以使用软件包配置验证处理 https://www.nuget.org/packages/MediatR.Extensions.FluentValidation.AspNetCore

只需插入配置部分:

services.AddFluentValidation(new[] {typeof(GenerateInvoiceHandler).GetTypeInfo().Assembly});

GitHub

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