我需要制作两个不同的AVG列,但似乎无法让它工作

时间:2017-05-21 18:58:42

标签: sql average

SELECT AVG(goals1) FROM matches
WHERE cid='1'
(SELECT AVG(goals2) FROM matches
WHERE cid='2')
;

3 个答案:

答案 0 :(得分:1)

SELECT AVG(goals1) AvgCid1, (SELECT AVG(goals2) FROM matches WHERE cid='2') AvgCid2
FROM matches
WHERE cid='1'

答案 1 :(得分:0)

在这些语句之间添加UNION

SELECT AVG(goals1) FROM matches
WHERE cid='1'
UNION
SELECT AVG(goals2) FROM matches
WHERE cid='2'

您可能还需要为列命名。

答案 2 :(得分:0)

这个怎么样?

SELECT * FROM
(SELECT AVG(goals1) AS goals1 FROM matches WHERE cid='1') t1
full outer join
(SELECT AVG(goals2) AS goals2 FROM matches WHERE cid='2') t2
ON t1.goals1 <> t2.goals2;
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