Question

运行此脚本时出现此错误：

使用“1”参数调用“匹配”的异常：“值不能空值。参数名称：输入“在V：\ compiler \ shitter2.ps1：3 char：1 + $ tables = $ regex.matches（（GC v：\ compiler \ test.txt -raw））。groups.value + ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~~~~~~~~~~ + CategoryInfo：NotSpecified：（:) []，MethodInvocationException + FullyQualifiedErrorId：ArgumentNullException

这是脚本代码：

$Path = 'V:\compiler\po.htm'
[regex]$regex = "(?s)<TABLE ID=.*?</TABLE>"
$tables = $regex.matches((GC v:\compiler\test.txt -raw)).groups.value
ForEach($String in $tables){
$table = $string.split("`n")
$CurTable = @()
$CurTableName = ([regex]'TABLE ID="
([^"]*)"').matches($table[0]).groups[1].value
$CurTable += ($table[1] -replace "</B></TH><TH><B>",",") -replace "</?
(TR|TH|B)>"
$CurTable += $table[2..($table.count-2)]|ForEach{$_ -replace "</TD>
<TD>","," -replace "</?T(D|R)>"}
$CurTable | convertfrom-csv | export-csv "$CurTableName.csv" -notype
}

Answer 1

您可能忘记了使用[1]访问该条目：

$tables = $regex.matches((GC v:\compiler\test.txt -raw)).groups[1].value

运行此脚本时，找不到txt错误

1 个答案: