Question

我正在尝试从firebase数据库中读取一个值，但我被卡住了。当我尝试对值进行快照时，函数.then（）没有被执行。

这是代码。

function checkPublishButton(){
  $( "#publish_button" ).click(function(){
  //Check if a user is logged in.
  firebase.auth().onAuthStateChanged(function(user) {
    //Declare firebase data-base
    var database = firebase.database();      
    //Get user's total event created counter
    return database.ref("users/" + user.uid ).once('value').then(function(snapshot) {
      console.log("This is not executing");
      return snapshot.val().total_event_created;
    }).then(function(counter) {
      //Increase the total_event_counter by one
      console.log("This is also not executing");
      var counter = counter +1;
      database.ref('users/'+user_id+'/total_event_created').set(counter);  
      //Get input from form
      var title = $("#title").val();
      var date = $("#date").val();
      var hour = $("#hour").val();
      var place = $("#place").val();
      var brief_description = $("#brief_description").val();
      var detailed_description = $("#detailed_description").val();
      var contact_email = $("#contact_email").val();
      var contact_phone_number = $("#contact_phone_number").val();
      var imageUrl = $("#imageUrl").val(); 
      //Post event into firebase database
      database.ref('events/' + user_id + '/' +  counter).set({
        title: title,
        date: date,
        hour: hour,
        place: place,
        brief_description: brief_description,
        detailed_description: detailed_description,
        contact_email: contact_email,
        contact_phone_number: contact_phone_number,
        imageUrl: imageUrl
      });
    });              
  });
});
}

所以，你可以知道这两个代码，因为没有执行console.log（）命令。

Answer 1

呀！代码不起作用。由于您在onAuthStateChanged回调中编写了所有代码，因此只有在身份验证状态发生更改时才会调用。（用户登录/注销）。在这里，我对你的代码进行了一些重构。希望这对你有帮助。

    <?php
    class Comments extends CI_Controller{

        public function create($post_id){
            $post_id = $this->input->post('post_id');
            $data['post'] = $this->Posts_model->get_posts($post_id);

            $this->form_validation->set_rules('name', 'Name', 'required');
            $this->form_validation->set_rules('email', 'Email', 'required');
            $this->form_validation->set_rules('body', 'Body', 'required');

            if($this->form_validation->run()===FALSE){
                $this->load->view('templates/header');
                $this->load->view('posts/view',$data);
                $this->load->view('templates/footer');
            }else {
                $this->comment_model->create_comment($post_id);
                redirect('posts/'.$slug);
            }
        }

    }
    ?>

**Comment Model**


<?php

class Comment_model extends CI_Model{

    public function __construct(){
        $this->load->database();
    }

    public function create_comment($post_id = NULL){
        $data=array(
            'post_id'=>$post_id,
            'name' => $this->input->post('name'),
            'email' => $this->input->post('email'),
            'body' => $this->input->post('body'),
        );
        return $this->db->insert('comments',$data);
    }

    public function get_comments($post_id){
        $query = $this->db->get_where('comments',array('post_id'=>$post_id));
        return  $query->result_array();
    }


}

为什么函数.then（）没有被执行？

1 个答案: