Question

我的任务是显示该经理的最低薪雇员的MGR和工资。

我需要排除MGR未知的任何人，并排除最低工资低于1000美元的任何群体。结果应按工资降序排列。

这是表格：

    +-------+--------+-----------+------+------------+-----------+-----------+------+
    | Empno | Ename  |    Job    | Mgr  |  Hiredate  |    Sal    |   Comm    | Dept |
    +-------+--------+-----------+------+------------+-----------+-----------+------+
    |  7839 | KING   | PRESIDENT |      | 11/17/1981 | $5,000.00 | $0.00     |   10 |
    |  7782 | CLARK  | MANAGER   | 7839 | 6/9/1981   | $2,450.00 | $0.00     |   10 |
    |  7934 | MILLER | CLERK     | 7782 | 1/23/1982  | $1,300.00 | $0.00     |   10 |
    |  7902 | FORD   | ANALYST   | 7566 | 12/3/1981  | $3,000.00 | $0.00     |   20 |
    |  7788 | SCOTT  | ANALYST   | 7566 | 12/9/1982  | $3,000.00 | $0.00     |   20 |
    |  7876 | ADAMS  | CLERK     | 7788 | 1/12/1983  | $1,100.00 | $0.00     |   20 |
    |  7369 | SMITH  | CLERK     | 7902 | 12/17/1980 | $800.00   | $0.00     |   20 |
    |  7566 | JONES  | MANAGER   | 7839 | 4/2/1981   | $0.00     | $0.00     |   20 |
    |  7698 | BLAKE  | MANAGER   | 7839 | 5/1/1981   | $2,850.00 | $0.00     |   30 |
    |  7499 | ALLEN  | SALESMAN  | 7698 | 2/20/1981  | $1,600.00 | $300.00   |   30 |
    |  7844 | TURNER | SALESMAN  | 7698 | 9/8/1981   | $1,500.00 | $0.00     |   30 |
    |  7521 | WARD   | SALESMAN  | 7698 | 2/22/1981  | $1,250.00 | $500.00   |   30 |
    |  7654 | MARTIN | SALESMAN  | 7698 | 9/28/1981  | $1,250.00 | $1,400.00 |   30 |
    |  7900 | JAMES  | CLERK     | 7698 | 12/3/1981  | $950.00   | $0.00     |   30 |
    +-------+--------+-----------+------+------------+-----------+-----------+------+

到目前为止，这是我的代码：

SELECT EMp.Mgr, EMp.Ename, EMp.Sal AS Sal
FROM EMp
GROUP BY EMp.Mgr, EMp.Ename, EMp.Sal
HAVING (((EMp.Mgr) Is Not Null) AND ((EMp.Sal)>1000))
ORDER BY EMp.Sal DESC;

我当前代码的问题在于它没有考虑最低工资参数。我认为这需要通过使用子查询来完成，但我完全确定如何继续使用...

有人可以帮忙吗？

Answer 1

试试这个：

SELECT EMp.Mgr, EMp.Ename, EMp.Sal AS Sal
FROM EMp
WHERE emp.Sal = (select MIN(sal) from emp as emp2 where emp2.MGr = emp.Mgr and emp2.sal > 1000)
GROUP BY EMp.Mgr, EMp.Ename, EMp.Sal
HAVING EMp.Mgr Is Not Null
ORDER BY EMp.Sal DESC;

Answer 2

请尝试

with one as 
(
SELECT EMp.Mgr,min(EMp.Sal) MinSlary
FROM EMp
GROUP BY EMp.Mgr
)
select a.Mgr,b.EName,b.Sal from one a
inner join Emp b on a.Mgr=b.Mgr and a.MinSlary=b.Sal
where a.Mgr is not null and a.MinSlary>1000

Answer 3

以下是基于杰拉德的回答，但是我在那里发表的评论中提到了对此的担忧：

SELECT Emp.Mgr, Emp.Ename, Emp.Sal AS Sal
FROM Emp
WHERE Emp.Sal=(SELECT MIN(sal)
               FROM Emp as Emp2
               WHERE Emp2.MGr = Emp.Mgr
               HAVING min(Emp2.sal) >= 1000)
GROUP BY Emp.Mgr, Emp.Ename, Emp.Sal
HAVING Emp.Mgr Is Not Null
ORDER BY Emp.Sal DESC;

使用您的样本数据，返回与Jerrad相同的行，除了省略那些与经理7839或7698的行。除此之外，这两个管理员工的薪水为$ 0和$ 950。我解释原始问题的方式（＆＃34;排除最低工资低于1000美元和＃34的任何群体），这些经理应从结果中排除。

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3 个答案: