使用Ajax检查用户名可用性

时间:2017-05-30 07:14:32

标签: javascript php html ajax mysqli

这是我第一次尝试使用Ajax,这个代码正在做的是当用户键入用户名时,应该触发ajax并告诉用户用户名是否可用。但是ajax文件没有做它想要做的事情,换句话说该函数没有被触发。知道为什么吗?

我从一本书中采用了这个例子。

HTML

<!DOCTYPE html>
<html>
<head>
    <title>Registration Form</title>

    <!-- Bootstrap Core CSS -->
    <link href="bootstrap/css/bootstrap.min.css" rel="stylesheet">

    <!-- Custom Fonts -->
    <link href="bootstrap/font-awesome/css/font-awesome.min.css" rel="stylesheet" type="text/css">

    <!-- Ajax -->
    <script src="ajax.js" type="text/javascript" language="javascript"></script>

    <!-- Ajax -->
    <script src="checkusername.js" type="text/javascript" language="javascript"></script>

</head>

<body>
    <div class="form-group">
        <form action="checkusername.php">
            <fieldset>
                <legend>Registration Form</legend>
                <p>
                Username: <br> <input name="username" onchange="check_username(this.form.username.value)" type="text" class="form-control" placeholder="Username" maxlength="20"  style="width:200px; display: inline;">
                <span id="username_label"></span>
                </p>
                <p>
                Password: <input type="password" class="form-control" placeholder="Password" maxlength="20" style="width:200px;">
                </p>

                <p>
                Confirm Password: <input type="text" class="form-control" placeholder="Confirm Password" maxlength="20" style="width:200px;">
                </p>

                <p>
                First Name: <input type="text" class="form-control" placeholder="First Name" maxlength="20" style="width:200px;">
                </p>
                <p>
                Last Name: <input type="text" class="form-control" placeholder="Last Name" maxlength="20" style="width:200px;">
                </p>
                <p>
                Email: <input type="email" class="form-control" placeholder="Email" maxlength="20" style="width:200px;">
                </p>

                <button type="submit" name="submit" class="btn" >Register</button>

            </fieldset>
        </form>
    </div>
</body>

</html>

ajax.js

var ajax = false;

if( window.XMLHttpRequest ){

    ajax = new XMLHttpRequest();

} else {
    // code for IE6, IE5
    ajax = new ActiveXObject("Microsoft.XMLHTTP");
}

if ( !ajax ) {
    alert('functionality is not avaible');
}

checkusername.js

function check_username( username ){

    if( ajax ){
        ajax.onreadystatechange = handle_check;
        ajax.open( 'GET', 'checkusername.php?username=' + encodeURIComponent(username), true);
        ajax.send(null);
    }
    else{

        document.getElementById( 'username_label' ).innerHTML = 'The availablity of this username will be check upon form submission';
    }
}

function handle_check(){

    if ( ajax.readyState == 4 && ajax.status == 200 ) {
        document.getElementById( 'username_label' ).innerHTML = ajax.responseText;
    }
}

checkusername.PHP

<?php

    if (isset($_GET['username'])) {

        $dbc = @mysqli_connect('localhost','root','','testdb') OR die ( 'Cannot connect.' );

        $que = sprintf("SELECT ID FROM maintable WHERE name='%s'", mysqli_real_escape_string( $dbc, trim( $_GET['username'] ) ));

        $runque = mysqli_query( $dbc, $que );

        if (mysqli_num_rows( $runque ) == 1) {
            echo "The Username is unavaiable!";
        }
        else{
            echo "The Username is avaiable!";
        }

        mysqli_close( $dbc );

    }
    else{
        echo "Please Enter username";
    }

?>

0 个答案:

没有答案
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