我没有使用此Python代码获得所需的结果。需要帮助。
当您输入符合条件的字符串时,应该停止while循环。
代码:
x = input("Enter input: ")
while (int(x[3]) != 1 or int(x[3]) != 2):
print("The fourth character must be a 1 or 2")
x = input("Enter input again: ")
答案 0 :(得分:4)
数字始终不等于1或2,您可能想要使用and
:
x = input("Enter input: ")
while int(x[3]) != 1 and int(x[3]) != 2:
print("The fourth character must be a 1 or 2")
x = input("Enter input again: ")
使用not in
更具可读性:
x = input("Enter input: ")
while int(x[3]) not in (1, 2):
print("The fourth character must be a 1 or 2")
x = input("Enter input again: ")
如果你想要一种更容忍失败的方式,请与字符串进行比较:
while True:
x = input("Enter input: ")
if x[3:4] in ('1', '2'):
break
print("The fourth character must be a 1 or 2.")