Question

我是使用php的新手，我正在为我的网页创建一个登录窗口，我想要比较来自输入的电子邮件和密码是否与数据库中的相同;我已经对电子邮件进行了比较，但我不知道如何检索该电子邮件的确切密码，并将其与密码输入进行比较，以了解它是否相同。这就是我对我的php：

$password=$_POST['password'];
$email=$_POST['email'];
$query = mysql_query( "SELECT email FROM Register WHERE email = '$email'");
$query2 = mysql_query( "SELECT password FROM Register WHERE email = '$email', password = '$password'");



    if(!$email)
    {
        if (!$password)
        {
            echo '
            <script>
            alert("Email and password are required.");
            window.history.go(-1);
            </script>';
            exit;
        }
        else
        {
            echo '
            <script>
            alert("Email Required.");
            window.history.go(-1);
            </script>';
            exit;
        }           
    }

    if (!$password)
    {
        echo '
        <script>
        alert("Password required.");
        window.history.go(-1);
        </script>';
        exit;
    }

    else
    {


        if(!mysql_num_rows($query))
        {
            echo '
            <script>
            alert("The email is not the same or does not exist");
            window.history.go(-1);
            </script>';
            exit;
        }

        if($query2==$password)
        {
            echo '
            <script>
            alert("Succesful Login");
            window.history.go(-1);
            </script>';
            exit;
        }

        else
        {
            echo '
            <script>
            alert("Password is not the same, please verify.");
            window.history.go(-1);
            </script>';
            exit;

        }




    }

顺便说一句，谢谢你的帮助

Answer 1

更改下面的查询

SELECT password FROM Register WHERE email = '$email' AND password = '$password'

也使用mysqli *，因为在Php 7中不推荐使用mysql *并完全删除

https://www.w3schools.com/php/php_ref_mysqli.asp

Answer 2

请试试这个

 mysqli_query( "SELECT * FROM Register WHERE email = '$email' and password ='$password'");

if(mysql_num_rows($query))
{
            echo '
            <script>
            alert("Succesful Login");
            window.history.go(-1);
            </script>';
            exit;
 }
else
{
            echo '
            <script>
            alert("The email is not the same or does not exist");
            window.history.go(-1);
            </script>';
            exit;

 }

Answer 3

你正在使用＆＃34;，＆＃34;而不是＆＃34; AND＆＃34;。使用，它将解决

执行第二次查询后，您的数据将在$ query中。你有使用

$data=mysql_fetch_array($query);
$data['password'];// there contains password
so you code this
if($query2==$password)
        {
            echo '
            <script>
            alert("Succesful Login");
            window.history.go(-1);
            </script>';
            exit;
        }
will be changed to
if($data['password']==$password)
        {
            echo '
            <script>
            alert("Succesful Login");
            window.history.go(-1);
            </script>';
            exit;
        }

MySQL使用电子邮件字段从数据库中检索密码字段

3 个答案: