我正在处理laravel中的第一个项目,现在我执行搜索功能,但是,我正在进行一个涉及多个左连接的查询,并且在搜索时返回一些冗余信息。
相关表格是这四个,查询如下:
$searchData = ProfessionalDetail::select('u.id as user_id','u.first_name','u.last_name','u.profile_pic','c.name as city_name','professional_details.avg_ratings')
->join('users as u' , 'u.id', '=' ,'professional_details.user_id')
->join('user_speciality as us' , 'us.user_id', '=' ,'professional_details.user_id')
->join('specialities as sp' , 'sp.id', '=' ,'us.speciality_id')
->join('cities as c' , 'c.id', '=' ,'professional_details.city_id')
->join('users_roles as ur' , 'ur.user_id', '=' ,'professional_details.user_id')
->where( function ( $q2 ) use ( $name) {
$q2->where('u.first_name' , 'like', '%' . $name . '%')
->orWhere('u.last_name','like', '%'.$name.'%')
->orWhere('u.first_name','like',$name.'%');
->orWhere('sp.name','like',$name.'%');
})
->where('ur.role_id' ,'=' , 2)
->paginate($num_per_page);
return $searchData;[![demo][1]][1]
我尝试过的是,按名称或专业(这是一个医生页面)列出了用户,当按专业准备时,一切进展顺利。但是,当我想要由用户列出时,请使用左连接' user_speciality'和' professional_details'。这使用户多次返回。
例如:
public function testApi(Request $request)
{
$users = ProfessionalDetail::searchByNameAndSpe("joshi", 10);
$i = 0;
if ($users) {
foreach ($users as $key => $value) {
$response["result"][] = $value;
$response["total"] = $i++;
}
} else {
return "error";
}
return $response;
}
返回:
{"result":[{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"Skin Specialist","city_name":"Pune","avg_ratings":"0.00"},{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"Heart Specialist","city_name":"Pune","avg_ratings":"0.00"},{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"ENT Specialist","city_name":"Pune","avg_ratings":"0.00"},{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"Kidney Specialist","city_name":"Pune","avg_ratings":"0.00"},{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"Eye Specialist","city_name":"Pune","avg_ratings":"0.00"}],"total":4}
Joshi只注册了一次,但是我知道他会被多次归还,因为他们之间的关系很多很多。因为他拥有几个专业。
现在,为了让它按专业搜索和用户名,我知道的唯一方法是使用左连接,我认为分离信息的方法是处理控制器中数组的信息但是我想知道这是否可以在查询中解决,因为我对SQL知之甚少,如果有任何方法我会非常感激,因为它可以节省我很多步骤来调试所有信息。
每个模型的方法
UserSpeciality表
public function users() {
return $this->belongsToMany('App\User', 'user_speciality', 'speciality_id', 'user_id');
}
用户
public function userSpeciality() {
return $this->belongsToMany('App\Speciality','user_speciality', 'user_id', 'speciality_id');
}
专业
public function users() {
return $this->belongsToMany('App\User', 'user_speciality', 'user_id', 'speciality_id');
}
ProfesionalDetail表
public function user(){
return $this->belongsTo("App\User");
}
答案 0 :(得分:0)
按用户ID尝试一次
GROUPBY(USER_ID)