Question

我一直试图＆＃34;在日期合并数组＆＃34;将数据显示到Google柱形图中。我想按年/月分组问题列表和成本。这是我的数据

array 
  0 => 
    array
      'date' => string '2017-03' 
      'source' => string 'Problem 1'
      'cost' => float 135
  1 => 
    array
      'date' => string '2017-03'
      'source' => string 'Problem 2'
      'cost' => float 385
  2 => 
    array
      'date' => string '2017-04'
      'source' => string 'Problem 3'
      'cost' => float 3500
  3 => 
    array 
      'date' => string '2017-04'
      'source' => string 'Problem 1'
      'cost' => float 4437.5
  4 => 
    array
      'date' => string '2017-04'
      'source' => string 'Problem 2'
      'cost' => float 318

所需的输出为https://jsfiddle.net/9d1fzsaf/1/

如果通过MySQL group by Date和问题源获取数据，我应该优化查询吗？

SELECT DATE_FORMAT(creation_date,'%Y-%m') AS date,
                ( CASE
                         WHEN source_problem = '0' THEN 'Empty'
                         WHEN source_problem = '1' THEN 'Problem 1'
                         WHEN source_problem = '2' THEN 'Problem 2'
                         WHEN source_problem = '3' THEN 'Problem 3'
                        ELSE 'Others'
                END ) AS source,
                            SUM(aprox_cost) AS cost
                        FROM table
                        WHERE source_problem IS NOT NULL
                        GROUP BY DATE_FORMAT(creation_date,'%Y-%m'),
                                 source_problem

任何帮助都将受到高度赞赏！谢谢

Answer 1

我修改了你的mysql查询。请使用此代码

 SELECT DATE_FORMAT(creation_date,'%Y-%m') AS date,
                    ( CASE
                             WHEN source_problem = '0' THEN 'Empty'
                             WHEN source_problem = '1' THEN 'Problem 1'
                             WHEN source_problem = '2' THEN 'Problem 2'
                             WHEN source_problem = '3' THEN 'Problem 3'
                            ELSE 'Others'
                    END ) AS source,
                                SUM(aprox_cost) AS cost
                            FROM table
                            HAVING source_problem IS NOT NULL
                            GROUP BY date;

Answer 2

为了在张贴的小提琴中制作图表，
每个source_problem都需要是一个单独的列

建议将sql中的列分开...

SELECT
  DATE_FORMAT(creation_date,'%Y-%m') AS Month,
  SUM(CASE
    WHEN source_problem = '0'
    THEN aprox_cost
    ELSE 0
  END) AS Empty,
  SUM(CASE
    WHEN source_problem = '1'
    THEN aprox_cost
    ELSE 0
  END) AS Problem1,
  SUM(CASE
    WHEN source_problem = '2'
    THEN aprox_cost
    ELSE 0
  END) AS Problem2,
  SUM(CASE
    WHEN source_problem = '3'
    THEN aprox_cost
    ELSE 0
  END) AS Problem3,
  SUM(CASE
    WHEN source_problem <> '0' AND source_problem <> '1' AND source_problem <> '2' AND source_problem <> '3'
    THEN aprox_cost
    ELSE 0
  END) AS Others
FROM
  table
WHERE
  source_problem IS NOT NULL
GROUP BY
  DATE_FORMAT(creation_date,'%Y-%m')

另外，在使用JSON数据时，它需要位于this format，
为了直接创建数据表......

var data = new google.visualization.DataTable(jsonData);

因此，构建类似于以下结果...

$data = array();

$data['cols'] = array(
  array('label' => 'Month', 'type' => 'string')
  array('label' => 'Empty', 'type' => 'number')
  array('label' => 'Problem 1', 'type' => 'number')
  array('label' => 'Problem 2', 'type' => 'number')
  array('label' => 'Problem 3', 'type' => 'number')
  array('label' => 'Others', 'type' => 'number')
);
$data['rows'] = array();

foreach ($results as $result) {
  $row = array(
    array('v' => (string) $result['Month'])
    array('v' => (float) $result['Empty'])
    array('v' => (float) $result['Problem1'])
    array('v' => (float) $result['Problem2'])
    array('v' => (float) $result['Problem3'])
    array('v' => (float) $result['Others'])
  );
  $data['rows'][] = array('c' => $row);
}

echo json_encode($data);

在日期合并数组以显示Google图表

2 个答案: