Question

如何使用此json字符串中的Newtonsoft.JSON（json.net）创建JSON数组

[
  {
    "Cells": {
      "results": [
        {
          "Key": "Title",
          "Value": "hello",
          "ValueType": "Edm.String"
        },
        {
          "Key": "Size",
          "Value": "54549",
          "ValueType": "Edm.Int64"
        },
        {
          "Key": "Path",
          "Value": "http://somesite/a/hello.pptx",
          "ValueType": "Edm.String"
        },
        {
          "Key": "Summary",
          "Value": "Some summary <ddd/> interesting reading <ddd/> nice book <ddd/> ",
          "ValueType": "Edm.String"
        },
        {
          "Key": "Name",
          "Value": "http://somesite",
          "ValueType": "Edm.String"
        }
      ]
    }
  },
  {
    "Cells": {
      "results": [
        {
          "Key": "Title",
          "Value": "hi joe",
          "ValueType": "Edm.String"
        },
        {
          "Key": "Size",
          "Value": "41234",
          "ValueType": "Edm.Int64"
        },
        {
          "Key": "Path",
          "Value": "http://someothersite/interesting/hi.pptx",
          "ValueType": "Edm.String"
        },
        {
          "Key": "Summary",
          "Value": "Some summary <ddd/> interesting reading <ddd/> nice book <ddd/> ",
          "ValueType": "Edm.String"
        },
        {
          "Key": "Name",
          "Value": "http://somesite",
          "ValueType": "Edm.String"
        }
      ]
    }
  }
]

json2csharp为我提供了以下这个结构的类

public class Result
{
    public string Key { get; set; }
    public string Value { get; set; }
    public string ValueType { get; set; }
}

public class Cells
{
    public List<Result> results { get; set; }
}

public class RootObject
{
    public Cells Cells { get; set; }
}

如何使用这些类创建json数组？

更新和解决方案

这将起作用

static void Main(string[] args)
{
    RootObject ro = new RootObject();
    Cells cs = new Cells();
    cs.results = new List<Result>();

    Result rt = new Result();
    rt.Key = "Title";
    rt.Value = "hello";
    rt.ValueType = "Edm.String";
    cs.results.Add(rt);

    Result rs = new Result();
    rs.Key = "Size";
    rs.Value = "3223";
    rs.ValueType = "Edm.Int64";
    cs.results.Add(rs);

    ro.Cells = cs;

    string json = JsonConvert.SerializeObject(ro);
}

Answer 1

您正在寻找功能DeserializeObject<T>：

var json = ""; // string up above in your code
var jObect = JsonConvert.DeserializeObject<RootObject>(json);

// Use

var cells = jObject.Cells;
var result1 = cells.results.FirstOrDefault();

Answer 2

这将起作用

static void Main(string[] args)
{
    RootObject ro = new RootObject();
    Cells cs = new Cells();
    cs.results = new List<Result>();

    Result rt = new Result();
    rt.Key = "Title";
    rt.Value = "hello";
    rt.ValueType = "Edm.String";
    cs.results.Add(rt);

    Result rs = new Result();
    rs.Key = "Size";
    rs.Value = "3223";
    rs.ValueType = "Edm.Int64";
    cs.results.Add(rs);

    ro.Cells = cs;

    string json = JsonConvert.SerializeObject(ro);
}

Answer 3

以下是POCO的一个例子：

    public class Account
{
    public string Email { get; set; }
    public bool Active { get; set; }
    public DateTime CreatedDate { get; set; }
    public IList<string> Roles { get; set; }
}

这可以通过反序列化下面显示的JSON字符串来实现：

    string json = @"{
   'Email': 'james@example.com',
   'Active': true,
   'CreatedDate': '2013-01-20T00:00:00Z',
   'Roles': [
     'User',
     'Admin'
   ]
 }";

Account account = JsonConvert.DeserializeObject<Account>(json);

Console.WriteLine(account.Email);

参考下面的Newtonsoft文档： http://www.newtonsoft.com/json/help/html/DeserializeObject.htm

Answer 4

如果你想要一个对象的字符串表示，特别是一个json对象，最相关的是.ToString（）。但是，由于其他原因，它可能会失败......

如何使用Newtonsoft.Json为此特定结构创建JSON数组

4 个答案: