Question

我正在创建一个解析输入json数据并存储在表中的过程。该函数如下所示：

create or replace function test_func(d json)
returns void as $$
  begin
    with n as (
     insert into t1 (name) values (d::json -> 'name') returning id
    ), c as (
     insert into t2 (cars) values json_array_elements_text(d::json -> 'cars') returning id
    )
    insert into t3 (id, name_id, cars_id, brand)
    select 1, n.id, c.id, json_array_elements_text(d::json -> 'brands') from n, c;
end;
$$ language plpgsql;


CREATE TABLE t1
(
  "id" SERIAL PRIMARY KEY,
  "name" text NOT NULL
)

CREATE TABLE t2
(
  "id" SERIAL PRIMARY KEY,
  "cars" text NOT NULL,
  "car_type" int
)

CREATE TABLE t3
(
  "id" int,
  "name_id" int REFERENCES t1(id),
  "cars_id" int REFERENCES t2(id),
  "brand" text
)

数据输入的名称为文本，汽车和品牌是数组，全部包装在json中。所以最后一个插入有混合值类型，如果这个人有两辆车，我有4行插入到t3因为c.id和json_array_elements_text（d :: json - ＆gt;＆＃39; brands＆＃39;）都有两个数据集合，2x2 = 4，如何将插入的值映射为一对一？因此，第一个c.id应该映射到第一品牌。

Answer 1

要映射它们，你必须加入不是true，而是加入不同的行。

这里是如何加入id with ordinality的示例 - 希望它会有所帮助。基于你的json样本

t=# with j as (select '{"name":"john", "cars":["bmw X5 xdrive","volvo v90 rdesign"], "brands":["bmw","volvo"]}'::json d)
select car,brand,t1.id from j
join json_array_elements_text(j.d->'cars') with ordinality t1(car,id) on true
join json_array_elements_text(j.d->'brands') with ordinality t2(brand,id) on t1.id = t2.id
;
        car        | brand | id
-------------------+-------+----
 bmw X5 xdrive     | bmw   |  1
 volvo v90 rdesign | volvo |  2
(2 rows)

更新详细阐述OP：

您可以通过聚合em然后使用index：

来避免映射多行

你的fn：

create or replace function test_func(d json)
returns void as $$
  begin
with j as (select d)
, a as (
  select car,brand,t1.id oid 
  from j
  join json_array_elements_text(j.d->'cars') with ordinality t1(car,id) on true
  join json_array_elements_text(j.d->'brands') with ordinality t2(brand,id) on t1.id = t2.id
)
, n as (
  insert into t1 (name) values (d::json -> 'name') returning id
), c as (
  insert into t2 (cars) select car from a order by oid returning id
)
, ag as (
  select array_agg(c.id) cid from c
)
insert into t3 (id, name_id, cars_id, brand)
  select 1, n.id,cid[oid], brand
  from a 
  join n on true
  join ag on true
;
end;
$$ language plpgsql;

你的桌子：

CREATE TABLE t1 ( "id" SERIAL PRIMARY KEY, "name" text NOT NULL );
CREATE TABLE t2 ( "id" SERIAL PRIMARY KEY, "cars" text NOT NULL );
CREATE TABLE t3 ( "id" int, "name_id" int REFERENCES t1(id), "cars_id" int REFERENCES t2(id), "brand" text );

<强>执行：

t=#   select test_func('{"name":"john", "cars":["bmw X5 xdrive","volvo v90 rdesign"], "brands":["bmw","volvo"]}');
 test_func
-----------

(1 row)

t=#   select * from t1;
 id |  name
----+--------
 14 | "john"
(1 row)

t=#   select * from t2;
 id |       cars
----+-------------------
 27 | bmw X5 xdrive
 28 | volvo v90 rdesign
(2 rows)

t=#   select * from t3;
 id | name_id | cars_id | brand
----+---------+---------+-------
  1 |      14 |      27 | bmw
  1 |      14 |      28 | volvo
(2 rows)

Postgresql插入select多行

1 个答案: