我正在尝试自动替换服务器上的站点地图文件。使用php和mysqli,我生成了所需的输出,但我无法弄清楚如何将该输出保存为.xml文件。
我已经阅读过有关使用php创建,打开和编写文件的内容,但我无法弄清楚如何获取生成的内容并将其放入文件中。有什么指针吗?
到目前为止,这是我的代码......
$my_file = 'sitemap.xml';
$handle = fopen($my_file, 'w') or die('Cannot open file: '.$my_file);
$data=""; //how do I include the code below as my 'data'?
<?php echo"<?xml version=\"1.0\" encoding=\"utf-8\" ?>"; ?>
<?php
include "connectScript.php";
$date = date("Y-m-d");
header("Content-type: text/xml");
?>
<urlset xmlns="http://www.sitemaps.org/schemas/sitemap/0.9">
<?php
$baseUrl="mysite.co.uk/page.php";
$query = "SELECT DISTINCT topic FROM db";
$result = $conn->query($query) or die (mysql_error($query));
while($row = $result->fetch_assoc()) {
$topic = $row['topic'];
$topic = "$baseUrl?t=${topic}";
?>
<url>
<loc>http://www.<?php echo $topic; ?></loc>
<lastmod><?php echo $date; ?></lastmod>
<changefreq>daily</changefreq>
<priority>1.00</priority>
</url>
<?php
}
?>
</urlset>
<?php
fwrite($handle, $data);
?>
&#13;
答案 0 :(得分:0)
尝试这样的事情:
$my_file = 'sitemap.xml';
$handle = fopen($my_file, 'w') or die('Cannot open file: '.$my_file);
$data=""; //how do I include the code below as my 'data'?
<?php ob_start();?> //start the output buffer
<?php echo"<?xml version=\"1.0\" encoding=\"utf-8\" ?>"; ?>
<?php
include "connectScript.php";
$date = date("Y-m-d");
//header("Content-type: text/xml");//remove this, this isn't an xml file it's a php file creating xml
?>
<urlset xmlns="http://www.sitemaps.org/schemas/sitemap/0.9">
<?php
$baseUrl="mysite.co.uk/page.php";
$query = "SELECT DISTINCT topic FROM db";
$result = $conn->query($query) or die (mysql_error($query));
while($row = $result->fetch_assoc()) {
$topic = $row['topic'];
$topic = "$baseUrl?t=${topic}";
?>
<url>
<loc>http://www.<?php echo $topic; ?></loc>
<lastmod><?php echo $date; ?></lastmod>
<changefreq>daily</changefreq>
<priority>1.00</priority>
</url>
<?php
}
?>
</urlset>
<?php
$data = ob_get_clean(); // set everything that was output above to the $data variable
fwrite($handle, $data);
?>
答案 1 :(得分:0)
有几种方法可以将数据保存到文件中,其中一种最简单的方法是(从手册中引用)
int file_put_contents ( string $filename , mixed $data [, int $flags = 0 [, resource $context ]] )
这只是fopen / fwrite / fclose的简化版本。然而,它确实会像你注意到的那样写一个字符串。
可以使用以下命令构建字符串:
$string = "Hello I'm a string.";
要附加更多内容,您可以使用
$string = $string . " And I'm another part.";
或使用assignment operator的较短版本:
$string .= " And I'm another part.";
也可以使用ob_start缓冲任何输出(打印的东西(print()/ echo / etc.),如下所示:
ob_start();
echo "Hello i'm a string.";
echo "And I'm another part.";
// do whatever more you need.
$content = ob_get_clean();
file_put_contents('file.txt', $content);