Question

我一直在用sap hana语法再次敲打我的脑袋。我一直在寻找一种编写函数或过程的方法，并在select语句中调用函数或过程来评估表中的列并根据if函数更改列。

我创建了大部分脚本但是替换功能没有按预期工作。我对sap hana不太熟悉，所以任何帮助都会受到赞赏。谢谢。

有人也可以告诉我如何调用该程序，因为这似乎在sap hana中有点复杂。我正在使用hana sp 10.

create procedure update_str   
language sqlscript   
as   

ip_str varchar:= '21222212';    

temp_str varchar(100) := ip_str || ',';   
pos integer :=1;   

begin   

while(length(:temp_str) > 0 ) do   

if substr(temp_str,1,1) = '1' and substr (temp_str,2,1) = '2' then   
update temp_str := replace(temp_str,'12','12,');   
pos := :pos + 1;   

elseif substr(temp_str,1,1) = '2' and substr (temp_str,2,1) = '1' then   
update temp_str := replace(temp_str,'21','2,1');   
pos := :pos + 1;   

elseif substr(temp_str,1,1) = '2' and substr (temp_str,2,1) = '2' then   
update temp_str := replace(temp_str,'22','2,2');   
pos := :pos + 1;   

else;   

end if;   
end if;   
end if;   

end while;     

end;

我基本上想要使用select语句运行函数或过程，并输出结果如下

我想要实现的例子

id |字符串更新|来自功能或程序的temp_str
1 | 12212 | 12,2,12
2 | 21221 | 2,12,2,1
3 | 12212 | 12,2,12

Answer 1

For what you described it is best to use a scalar user-defined function (SUDF).
How to create and use those is explained extensively in the SAP HANA Developer Guide, so I won't go into details here.

I also won't discuss the logic errors in the provided code, instead here is a version that generates the output for your test data:

drop function update_str;
create function update_str (IN IP_STR varchar(100) ) 
        returns res_str varchar(200)
language sqlscript   
as   
begin   
declare temp_str varchar(100) := ip_str ;   

    -- add a comma behind twelves
    temp_str := replace (:temp_str, '12', '12,');

    -- add a comma between twenty-ones
    temp_str := replace (:temp_str, '21', '2,1');

    -- add a comma between twenty-twos
    temp_str := replace (:temp_str, '21', '2,1');

    -- remove last comma if there is any
    if (right (:temp_str, 1) = ',' ) then
        temp_str =  left (:temp_str, length(:temp_str) -1 );
    end if;

    res_str :=  :temp_str;
end;

Check the code:

with test_data as 

          ( select 1 as id, '12212' as str from dummy
union all select 2 as id, '21221' as str from dummy
union all select 3 as id, '12212' as str from dummy)
select id, str, update_str(str)
from test_data;

ID  STR     UPDATE_STR(STR)  
1   12212   12,2,12        
2   21221   2,12,2,1       
3   12212   12,2,12

Depending on your actual requirement you might be able to form a regular expression that performs the same transformation. If so, you could also use the REPLACE_REGEXPR function in SAP HANA.

在sap hana中的select语句中调用过程或函数

1 个答案: