Question

如何将碰撞的值插入结果表？这就是我尝试过的事情：

for elements in collisions:
    for i in results:
        for j in i:
            results[i][j] = elements


collisions = [26, 12, 16, 17, 12, 16, 14, 8, 4, 2, 8, 5, 3, 4, 5, 3, 2, 3, 2, 6, 2, 2, 2, 3, 0, 0, 0, 0]


result = [[0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0]]

想要：

[[26, 12, 4, 3, 2, 2, 0], [12, 16, 2, 4, 3, 2, 0], [16, 14, 8, 5, 2, 2, 0], [17, 8, 5, 3, 6, 3, 0]]

提前致谢

Answer 1

这是将列表分解为子列表的简单方法。

x=0
result = []
collisions = [26, 12, 16, 17, 12, 16, 14, 8, 4, 2, 8, 5, 3, 4, 5, 3, 2, 3, 2, 6, 2, 2, 2, 3, 0, 0, 0, 0]
while x < len(collisions)/7:
    sub_list = []
    for i in range(x,len(collisions),4):
        sub_list.append(collisions[i])
    result.append(sub_list)
    x += 1
print collisions
print result 
[26, 12, 16, 17, 12, 16, 14, 8, 4, 2, 8, 5, 3, 4, 5, 3, 2, 3, 2, 6, 2, 2, 2, 3, 0, 0, 0, 0]
[[26, 12, 4, 3, 2, 2, 0], [12, 16, 2, 4, 3, 2, 0], [16, 14, 8, 5, 2, 2, 0], [17, 8, 5, 3, 6, 3, 0]]

注意：没有错误检查

将元素插入元素列表元素中

1 个答案: