如何将列表转换为元组列表？

Question

以下是我在文本文件中的内容：

1712 Albert
1703 Benny
1799 Henry
1735 Jessica
1722 Lucas
1701 Luke
1757 William
1777 Jenny
1783 Lucia
1764 Venus
1718 Felicitas

这是我为阅读文件所做的工作，但我不知道如何将它们放入元组列表中

def readRecords(filepath):
    file = open('Students1.txt', 'r')
    filecontent = file.readlines()
    file.close()
    return filecontent

这是输出应该是什么：

Answer 1

def readRecords(filepath):
    result = []
    with open('Students1.txt', 'r') as f:  # close the file outside of `with`
        for line in f:  # Iterate over lines
            num, name = line.split()  # split line into two part
            num = int(num)  # convert number part to `int`
            result.append((num, name))
    return result

注意：除非您需要一次使用整行，否则请勿使用readlines()。你一次只需要一条线;迭代文件就足够了。

Answer 2

只需打开文件，然后拆分这些行，我意识到您需要的结果就像(int, string)，因此您可以使用map执行此操作，然后返回元组：

with open('out.csv') as f:
    print([tuple(map(lambda x: int (x) if x.isdigit() else x,i.split())) for i in f])

输出：

[(1712, 'Albert'), (1703, 'Benny'), (1799, 'Henry'), (1735, 'Jessica'), (1722, 'Lucas'), (1701, 'Luke'), (1757, 'William'), (1777, 'Jenny'), (1783, 'Lucia'), (1764, 'Venus'), (1718, 'Felicitas')]

Answer 3

def readRecords(filepath):
   rst = []
   with open(filepath) as f:
        data = f.read().splitlines()
        rst = [(int(x.split(' ')[0]), x.split(' ')[1]) for x in data]
   return rst

Answer 4

您必须遍历刚刚阅读的文件中的行。这是你能做的：

def readRecords(filepath):
    file = open(filepath, 'r')  # You should use the filepath variable you've given
    filecontent = file.readlines()
    file.close()

    my_tuples = []
    for line in filecontent:  # For each line in the file...
        line = line.strip()  # Remove the newline character which you likely don't want
        my_tuples.append(int((line.split(' ')[0]), line.split(' ')[1]))  # Create a tuple of the two words separated by a space

    return my_tuples

print(readRecords('Students1.txt'))

Answer 5

根据您从文件中读取的行，如下所示：

def process_lines(lines):
    result = []
    for line in lines:
        parts = line.strip().split(" ")
        result.append(tuple(int(parts[0]), parts[1]))
    return result

这里可以进行列表理解，但这需要很多紧张。在简化代码时使用listcomps，当它们变得更复杂时避免使用它们。 （或当他们要求你计算两次相同的值时）

Answer 6

如果你想要一个很好的短两行方法：

lines = [x.rstrip() for x in open('students.txt')]
output = [tuple(pair.split(' ')) for pair in lines]

print(output)
# [('1712', 'Albert'), ('1703', 'Benny'), ('1799', 'Henry')...

Answer 7

Location = ["1712","1703","1799",...]
Name = ["Albert","Benny","Henry",...]

使用zip功能：

z = zip(Location, Name)
print z

输出：

[("1712","Albert"),("1703","Benny"),...]