Question

我试图在我的sql数据库中插入两个语句。但是当我点击发送时，我看到只发布了第一个语句。

有人知道我的代码有什么问题以及如何解决它？

这是我的代码：

$query1 = "INSERT INTO table1(firstname, lastname) VALUES (?, ?)";
$stmt1 = $db->prepare($query1);
$stmt1->execute(array($firstname, $lastname));

$query2 = "INSERT INTO table2(firstname, lastname) VALUES (?, ?)";
$stmt2 = $db->prepare($query2);
$stmt2->execute(array($firstname, $lastname));

Answer 1

您不能总是假设您的查询始终有效。查询失败的原因有很多。无论何时执行查询，都必须检查一切是否正常。还可以打开错误报告以及检查错误日志。这个问题也应该在那里报告

以下修改将有助于过滤查询失败的问题

<?php
   error_reporting(E_ALL);

    $query2 = "INSERT INTO table2(`firstname`, `lastname`) VALUES (?, ?)";
    $stmt2 = $db->prepare($query2);
    if($stmt2->execute(array($firstname, $lastname))){//check if it saved
      echo 'Saved';
    } else {
      echo 'Failed Because '.$stmt2->error;//Oops something happened
    }

Answer 2

试试这个==＆gt;

$query1 = "INSERT INTO table1(firstname, lastname) VALUES (?, ?)";
$stmt1 = $db->prepare($query1);
$stmt1->bind_param("ss",$firstname, $lastname);
$stmt1->execute();

$query2 = "INSERT INTO table2(firstname, lastname) VALUES (?, ?)";
$stmt2 = $db->prepare($query2);
$stmt2->bind_param("ss",$firstname, $lastname);
$stmt2->execute();

在此处查看有关PHP Prepared Statements

的更多信息

Answer 3

当您prepare sql语句时，您可以在尝试执行sql之前检查一切正常，然后通过为execute方法的结果分配变量，检查是否存在成功查询并继续下一个语句。

Two very basic tables - identical except in name.

mysql> describe table1;
+-----------+-------------+------+-----+---------+-------+
| Field     | Type        | Null | Key | Default | Extra |
+-----------+-------------+------+-----+---------+-------+
| firstname | varchar(50) | YES  |     | NULL    |       |
| lastname  | varchar(50) | YES  |     | NULL    |       |
+-----------+-------------+------+-----+---------+-------+

mysql> describe table2;
+-----------+-------------+------+-----+---------+-------+
| Field     | Type        | Null | Key | Default | Extra |
+-----------+-------------+------+-----+---------+-------+
| firstname | varchar(50) | YES  |     | NULL    |       |
| lastname  | varchar(50) | YES  |     | NULL    |       |
+-----------+-------------+------+-----+---------+-------+




mysql> select * from table1;select * from table2;
+------------------------+-----------------------+
| firstname              | lastname              |
+------------------------+-----------------------+
| firstname59365bf480611 | lastname59365bf480613 |
+------------------------+-----------------------+
1 row in set (0.00 sec)

+------------------------+-----------------------+
| firstname              | lastname              |
+------------------------+-----------------------+
| firstname59365bf480611 | lastname59365bf480613 |
+------------------------+-----------------------+
1 row in set (0.00 sec)





$firstname=uniqid('firstname');
$lastname=uniqid('lastname');



$dbhost =   'localhost';
$dbuser =   'root'; 
$dbpwd  =   ''; 
$dbname =   '';
$db     =   new mysqli( $dbhost, $dbuser, $dbpwd, $dbname );




$result = false;

$sql='insert into `table1` (`firstname`, `lastname`) values (?, ?)';
$stmt = $db->prepare( $sql );

if( $stmt ){

    $stmt->bind_param('ss',$firstname, $lastname );
    $result = $stmt->execute();
    $stmt->free_result();
    $stmt->close();

} else {
    exit( 'Error: Statement #1' );
}
if( $result ){

    $sql='insert into `table2` (`firstname`, `lastname`) values (?, ?)';
    $stmt = $db->prepare( $sql );

    if( $stmt ){

        $stmt->bind_param('ss',$firstname, $lastname );
        $result = $stmt->execute();
        $stmt->free_result();
        $stmt->close();

    } else {
        exit( 'Error: Statement #2' );
    }
}
$db->close();

将两个语句发布到数据库中

3 个答案: