Question

我有这个问题：

SELECT "I1" & "," & "I2" AS Item_set, Round(Sum([T1].Fuzzy_Value)/Count(*),15) AS Support
    FROM (SELECT *
    FROM Prune AS t
    WHERE t.Trans_ID IN 

        (SELECT t1.Trans_ID FROM (

         SELECT *FROM Prune WHERE [Nama]="I1")  AS t1 
         INNER JOIN (SELECT * FROM Prune WHERE [Nama]="I2")  AS t2 ON t1.Trans_ID = t2.Trans_ID)

    AND t.Nama IN ("I1","I2"))  AS T1;

并且ttrans查询

SELECT Count([Trans_ID].[Trans_ID]) AS Expr1
FROM Trans_ID;

我需要更改Count (*)：

 SELECT "I1" & "," & "I2" AS Item_set, Round(Sum([T1].Fuzzy_Value)/Count(*),15)

进入ttrans查询。

我尝试过使用

SELECT "I1" & "," & "I2" AS Item_set, Round(Sum([T1].Fuzzy_Value)/ttrans.Expr1,15) AS Support
FROM (SELECT *
FROM Prune AS t
WHERE t.Trans_ID IN 

    (SELECT t1.Trans_ID FROM (

     SELECT *FROM Prune WHERE [Nama]="I1")  AS t1 
     INNER JOIN (SELECT * FROM Prune WHERE [Nama]="I2")  AS t2 ON t1.Trans_ID = t2.Trans_ID)

AND t.Nama IN ("I1","I2"))  AS T1, ttrans;

但是我得到了这样的错误：

You tried to execute a query that does not include the specified expression 
'Round(sum([T1].Fuzzy_Value/ttrans.Expr1,15)' as part of an aggregate function

任何想法如何修复它？

注意：我正在尝试在事务数据库中找到所有项目的2个组合并获得这样的结果

ITEM       Support
I1, I2     0.xxxxxxxxx

支持是（包含项目I1和I2 /总交易的总交易） - ＆gt;请注意，我正在使用ttrans查询来获取总交易价值

note2：我正在使用MS Access 的注3：

Ttrans表将如下所示

Expr1
270200

Answer 1

尝试：

SELECT "I1" & "," & "I2" AS Item_set, Round(Sum([T1].Fuzzy_Value)/ttrans.Expr1,15) AS Support
FROM (SELECT *
FROM Prune AS t
WHERE t.Trans_ID IN 

    (SELECT t1.Trans_ID FROM (

     SELECT *FROM Prune WHERE [Nama]="I1")  AS t1 
     INNER JOIN (SELECT * FROM Prune WHERE [Nama]="I2")  AS t2 ON t1.Trans_ID = t2.Trans_ID)

AND t.Nama IN ("I1","I2"))  AS T1, ttrans
GROUP BY "I1" & "," & "I2"

Answer 2

不知怎的，我找到了答案：

我尝试使用

SELECT "I1" & "," & "I2" AS Item_set, Round(Sum([T1].Fuzzy_Value)/sum(ttrans.Expr1),15)

它很奇怪

结合两个MS Access查询

2 个答案: