从两个范围之间的数据库中获取数据?

时间:2017-06-13 13:49:23

标签: php mysql codeigniter

我尝试获取用户的离开报告,我想在两个范围之间获取数据,以及离开日期是否在所选范围之间。 例如 这是我的数据库 enter image description here 假设我选择了2017-06-13至2017-06-17的范围,那么应选择第二排,假设我选择了2017-06-21至2017-06-25的范围,那么它也应该被选中我试过在两个不同的查询下面得到相同的结果

(a)中

(SELECT u.user_id, u.user_image, u.user_first_name, u.user_last_name, CONCAT(u.user_first_name, ' ', u.user_last_name) AS user_name, 
        u.user_email, p.driver_number, l.status, DATE_FORMAT(l.from_date, '%d-%m-%Y') as from_date, DATE_FORMAT(l.to_date, '%d-%m-%Y') as to_date 
        FROM (`bat_usermst` u) 
        JOIN `bat_leavemst` l ON `u`.`user_id` = `l`.`user_id` 
        JOIN `bat_profilemst` p ON `u`.`user_id` = `p`.`user_id` 
        WHERE `l`.`from_date` >= '" . $start . "' AND `l`.`from_date` <= '" . $end . "' AND 
        `l`.`status` = '1' AND `u`.`user_type` = 5 AND `u`.`user_status` = '1' AND `u`.`is_deleted` = '0' 
        ORDER BY `user_name`)

        UNION

        (SELECT u.user_id, u.user_image, u.user_first_name, u.user_last_name, CONCAT(u.user_first_name, ' ', u.user_last_name) AS user_name, 
        u.user_email, p.driver_number, l.status, DATE_FORMAT(l.from_date, '%d-%m-%Y') as from_date, DATE_FORMAT(l.to_date, '%d-%m-%Y') as to_date 
        FROM (`bat_usermst` u) 
        JOIN `bat_leavemst` l ON `u`.`user_id` = `l`.`user_id` 
        JOIN `bat_profilemst` p ON `u`.`user_id` = `p`.`user_id` 
        WHERE `l`.`to_date` >= '" . $start . "' AND `l`.`to_date` <= '" . $end . "' AND 
        `l`.`status` = '1' AND `u`.`user_type` = 5 AND `u`.`user_status` = '1' AND `u`.`is_deleted` = '0' 
        ORDER BY `user_name`)
        ";

(b)中

$this->db->select("u.user_id, u.user_image, u.user_first_name, u.user_last_name, CONCAT(u.user_first_name,' ', u.user_last_name) AS user_name,u.user_email, p.driver_number,l.status,
        DATE_FORMAT(l.from_date, '%d-%m-%Y') as from_date,
        DATE_FORMAT(l.to_date, '%d-%m-%Y') as to_date", FALSE);

        $this->db->from('usermst u');
        $this->db->join('bat_leavemst l', 'u.user_id = l.user_id');
        $this->db->join('profilemst p', 'u.user_id = p.user_id');
        $this->db->where('l.from_date >=', "$start");
        $this->db->where('l.to_date <=', "$end");
        $this->db->where('l.status', '1');
        $this->db->where(array('u.user_type' => DRIVER, 'u.user_status' => '1', 'u.is_deleted' => '0'));

        $this->db->order_by('user_name');
        $result = $this->db->get();

提前致谢。

1 个答案:

答案 0 :(得分:0)

正如我可以看到你的联合查询,查询的部分区别只有一个区别。 通常,只要你有复杂的where条件,就可以像在MySQL中编写的那样简单地指定这些条件。下面的代码应该给出所需的结果。

$where = "((`l`.`from_date` >= '" . $start . "' AND `l`.`from_date` <= '" . $end . "') ".
         "OR (`l`.`to_date` >= '" . $start . "' AND `l`.`to_date` <= '" . $end . "')) ".
          "AND `l`.`status` = '1' AND `u`.`user_type` = 5 AND `u`.`user_status` = '1' AND `u`.`is_deleted` = '0'";
        $this->db->from('usermst u');
        $this->db->join('bat_leavemst l', 'u.user_id = l.user_id');
        $this->db->join('profilemst p', 'u.user_id = p.user_id');
        $this->db->where($where,NULL,FALSE);
        $this->db->order_by('user_name');
        $result = $this->db->get();
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