Question

当用户与其他用户共享应用中的特定内容时，我有一个使用深层链接导航到页面的应用。这在第二个用户已经运行的应用程序时有效，但如果应用程序未运行，则只需打开应用程序并保留在主屏幕上。我知道我必须在这里遗漏一些非常简单的东西，但我无法弄清楚，并且无法在谷歌上找到任何关于此的答案。

我在AppDelegate.swift中的代码：

func application(_ application: UIApplication, open url: URL, sourceApplication: String?, annotation: Any) -> Bool {
        let urlPath : String = url.path as String!
        let urlHost : String = url.host as String!
        let mainStoryboard: UIStoryboard = UIStoryboard(name: "Main", bundle: nil)

        if(urlHost != "example.com")
        {
            print("Call Not From Correct Host. Not Continuing...")
            return false
        }

        if(urlPath == "/articles"){

            let article: ArticleDetailsViewController = mainStoryboard.instantiateViewController(withIdentifier: "ArticleDetailsViewController") as! ArticleDetailsViewController
            self.window?.rootViewController = article
        } 
        self.window?.makeKeyAndVisible()
        return true
    }

    func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
        // Override point for customization after application launch.

        return true
    }

Answer 1

这是正确的行为。您应该在appliction(_: didFinishLaunchingWithOptions:)

中处理它

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
    // Override point for customization after application launch.
    if let url = launchOptions[.url] as? URL, let annotation = launchOptions[.annotation] {
        return self.application(application, open: url, sourceApplication: launchOptions[.sourceApplication] as? String, annotation: annotation)
    }
    return true
}

Answer 2

如果您使用的是sceneDelegate scene(_ scene: UIScene, willConnectTo session: UISceneSession, options connectionOptions: UIScene.ConnectionOptions) 函数将在应用程序在终止状态后启动时起作用。

用于深层链接的

url 将在 connectionOptions.urlContexts

中可用

 func scene(_ scene: UIScene, willConnectTo session: UISceneSession, options connectionOptions: UIScene.ConnectionOptions) {
    navigateToDeepLinkScreen(urlContexts: connectionOptions.urlContexts)
}

Answer 3

对于Swift4.2

if launchOptions != nil{
        let launch = launchOptions![UIApplicationLaunchOptionsKey.userActivityDictionary]! as! Dictionary <String,Any>

        if ((launch["UIApplicationLaunchOptionsUserActivityKey"]! as! NSUserActivity).webpageURL != nil){
            if defaults.bool(forKey: DEFAULTS_IS_FIRST_START){
                print((launch["UIApplicationLaunchOptionsUserActivityKey"]! as! NSUserActivity).webpageURL)
            }
        }
    }

Answer 4

func application(_ application: UIApplication,
                 didFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey: Any]?) -> Bool {

    if let url = launchOptions?[.url] as? URL {
        return handleWidgetUrl(url)
    }

    return true
}
// Custom function to handle url and do some actions
private func handleWidgetUrl(_ url: URL) -> Bool {}

深层链接仅在应用正在运行时才有效

4 个答案: