Question

我试图使用NewtonSoft json 4.5解析以下json字符串：

public class Parent
{
   public string Name { get; set; }

   [JsonProperty(PropertyName = "Children")]
   public List<Child> Childs { get; set; }
}

public class Child {
   public string Name { get; set; }

   [JsonProperty(PropertyName = "Grandchildren")]
   public List<GrandChild> GrandChilds { get; set; }
}

public class GrandChild {
   [JsonProperty(PropertyName = "")]
   public string Name { get; set; }
}

我将序列化为json的对象看起来像这样：

async function asyncFunc() {
  try {
    await somePromise();
  } catch (error) {
    throw new Error(error);
  }
}

我已尝试将属性名称设置为空，但它无法解决问题。

Answer 1

您应该将List<GrandChild>替换为List<string>，或者为JsonConverter添加自定义GrandChild。

[JsonConverter(typeof(GrandChildConverter))]
public class GrandChild
{
    public string Name { get; set; }
}

public class GrandChildConverter : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return objectType == typeof(GrandChild);
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        writer.WriteValue(((GrandChild)value).Name);
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        return new GrandChild { Name = reader.Value.ToString() };
    }
}

跳过属性名称，仅使用json中的值

1 个答案: