Question

需要计算每天添加的用户数量，给定日期和日期的日期范围，例如如下所示：

select 
  '2017-06-01' as myDate
, count(distinct user_id) 
from tbl_stats 
where date(dateTime)<='2017-06-01' 
union all 
select
  '2017-06-02' as myDate
, count(distinct user_id) 
from tbl_stats 
where date(dateTime)<='2017-06-02'

输出如下：

 reportDate | count 
------------+-------
 2017-06-01 |  2467
 2017-06-02 |  2470

所以，我将只有fromDate和toDate，我需要在表中明确区分不同的用户数。我不会使用任何程序或循环。

Answer 1

SELECT DATE(ts.dateTime) AS reportDate
    , COUNT(distinct ts.user_id) AS userCount
FROM tbl_stats AS ts
WHERE ts.dateTime >= @lowerBoundDate 
    AND ts.dateTime < TIMESTAMPADD('DAY', 1, @upperBoundDate)
GROUP BY DATE(ts.dateTime)

Answer 2

要获得每天累计（不同）用户数，请使用以下内容，将以下示例中给出的自定义日期替换为开始日期和结束日期。

WITH test_data AS (
        SELECT '2017-01-01'::date as event_date, 1::int as user_id
        UNION
        SELECT '2017-01-01'::date as event_date, 2::int as user_id
        UNION
        SELECT '2017-01-02'::date as event_date, 1::int as user_id
        UNION
        SELECT '2017-01-02'::date as event_date, 2::int as user_id
        UNION
        SELECT '2017-01-02'::date as event_date, 3::int as user_id
        UNION
        SELECT '2017-01-03'::date as event_date, 4::int as user_id
        UNION
        SELECT '2017-01-03'::date as event_date, 5::int as user_id
        UNION
        SELECT '2017-01-04'::date as event_date, 1::int as user_id
        UNION
        SELECT '2017-01-04'::date as event_date, 2::int as user_id
        UNION
        SELECT '2017-01-04'::date as event_date, 3::int as user_id
        UNION
        SELECT '2017-01-04'::date as event_date, 4::int as user_id
        UNION
        SELECT '2017-01-04'::date as event_date, 5::int as user_id
        UNION
        SELECT '2017-01-04'::date as event_date, 6::int as user_id
        UNION
        SELECT '2017-01-05'::date as event_date, 3::int as user_id
        UNION
        SELECT '2017-01-05'::date as event_date, 4::int as user_id
        UNION
        SELECT '2017-01-05'::date as event_date, 5::int as user_id
        UNION
        SELECT '2017-01-05'::date as event_date, 6::int as user_id
        UNION
        SELECT '2017-01-05'::date as event_date, 7::int as user_id
        UNION
        SELECT '2017-01-05'::date as event_date, 8::int as user_id
        UNION
        SELECT '2017-01-06'::date as event_date, 7::int as user_id
        UNION
        SELECT '2017-01-06'::date as event_date, 9::int as user_id
)
SELECT event_date,
       COUNT(distinct user_id) AS distinct_user_per_day,
       SUM(COUNT(distinct user_id)) OVER (ORDER BY event_date) AS cumulative_user_count
FROM test_data
WHERE event_date >= '2017-01-01' 
      AND 
      event_date <= '2017-01-06'
GROUP BY 
      event_date

SQL：查询获取日期明智的增量

2 个答案: