Question

我对脚本非常陌生，我希望在google电子表格上获得一个非常简单的脚本，以便在每次触发时创建一个1到150个奇数的随机数列。

问题是无论我在脚本框中放置什么来实际运行，它总是会出现：

此脚本的OAuth标识已被删除或禁用。这可能是由于服务条款违规造成的。

经过一些谷歌搜索后，我发现问题与脚本的身份验证有关，但即使我运行以下教程脚本，我也会遇到同样的错误：

function createAndSendDocument() {
  // Create a new Google Doc named 'Hello, world!'
  var doc = DocumentApp.create('Hello, world!');

  // Access the body of the document, then add a paragraph.
  doc.getBody().appendParagraph('This document was created by Google Apps Script.');

  // Get the URL of the document.
  var url = doc.getUrl();

  // Get the email address of the active user - that's you.
  var email = Session.getActiveUser().getEmail();

  // Get the name of the document to use as an email subject line.
  var subject = doc.getName();

  // Append a new string to the "url" variable to use as an email body.
  var body = 'Link to your doc: ' + url;

  // Send yourself an email with a link to the document.
  GmailApp.sendEmail(email, subject, body);
}

Answer 1

Per @Zig Mandel-这是一个错误

这是一个可以帮助您的随机数字脚本。

＆＃13;

function ranNum() {
   // assume the array starts in A1 and runs down colA
   var sheet = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();

   // getValues() returns an array
  var range = sheet.getRange(1,1,sheet.getLastRow(),1).getValues();
  
  var num = "";
  num += Math.floor(Math.random() * 150 + 1);
 

  // Loop through every element in the range
  for(var j in range) {
    if(range[j].toString() == num) {
      Logger.log('matched');
    } else {

      // Write one code to the next line and stop the loop
      sheet.getRange((sheet.getLastRow()+1), 1).setValue(num);
      break
    }
  }
}

＆＃13;

Google Spreadsheet，运行任何脚本时都会出错（甚至是教程）

1 个答案: