Downloading file with pysftp

Question

I'm trying to load (and directly save locally) a .csv file stored on a FTP Server (SFTP protocol). I'm using Python in combination with pysftp library. When I check if the file exists, it returns TRUE. But when trying to load the file, it seems to be empty, whatever I try.

How can I get (and store) the file to my local environment? Do I miss something obvious?

import pysftp

cnopts = pysftp.CnOpts()
cnopts.hostkeys = None

# Make connection to sFTP
with pysftp.Connection(hostname,
                       username=sftp_username,
                       password=sftp_pw,
                       cnopts = cnopts
                       ) as sftp:
    sftp.isfile('directory/file.csv')) ## TRUE
    file = sftp.get('directory/file.csv')
    print(file) ## None

sftp.close()

Answer 1

Connection.get不返回任何内容。它将远程文件下载到localpath参数指定的本地路径。如果未指定参数，则会将文件下载到当前工作目录。

所以你想要这个：

sftp.get('directory/file.csv', '/local/path/file.csv')

如果您真的想要将文件读取到变量（我理解您实际上不需要），则需要使用Connection.getfo，例如：

flo = BytesIO()
sftp.getfo(remotepath, flo)

或者，直接使用Paramiko库（不使用pysftp包装器） 请参阅Read a file from server with SSH using Python。