Question

我有2个查询。第一个是找到净额，第二个是预算总和。我需要显示结果，包括来自差异表的商店名称和商店号。

以下是我查找总netamount的第一个查询：

SELECT sum(a.netamt) as netamt, b.store_name 
  FROM site_sales a JOIN site_store b ON b.storenum = a.storenum 

  WHERE a.busidate >= '2017-01-01' AND a.busidate <='2017-04-30'
  GROUP BY a.storenum

第二个查询是查找总预算

SELECT

SUM(CASE WHEN c.busidate BETWEEN '2017-01' AND '2017-04' THEN c.budget ELSE 0 END) as budget,
b.store_name
FROM site_kpimthslsbgt c JOIN site_store b ON b.storenum = c.storenum 
GROUP BY c.storenum

我需要结合这两个查询。输出的结果应该是 like this

Answer 1

试试这个如果在你的个人查询中提取了多条记录，你最后还需要建立连接条件：

Select x.netamt, y.budget, y.store_name
from
(
SELECT sum(a.netamt) as netamt, b.store_name 
FROM site_sales a JOIN site_store b ON b.storenum = a.storenum 
WHERE a.busidate >= '2017-01-01' AND a.busidate <='2017-04-30'
GROUP BY a.storenum
) x
inner join
(
SELECT
SUM(CASE WHEN c.busidate BETWEEN '2017-01' AND '2017-04' THEN c.budget ELSE 0 END) as budget,
b.store_name
FROM site_kpimthslsbgt c JOIN site_store b ON b.storenum = c.storenum 
GROUP BY c.storenum
) y
on x.store_name = y.store_name

Answer 2

SELECT sum(a.netamt) as netamt,SUM(CASE WHEN c.busidate BETWEEN '2017-01' AND '2017-04' THEN c.budget ELSE 0 END) as budget,b.store_name
FROM site_store b
JOIN site_kpimthslsbgt c ON b.storenum = c.storenum 
JOIN site_sales a ON  b.storenum = a.storenum 
GROUP BY b.storenum

尝试以上查询。

希望这会对你有所帮助。

Answer 3

我认为这里有4种可能的情况，有销售和预算的商店，有销售但没有预算的商店，有预算但没有销售的商店，既没有销售也没有预算的商店。

鉴于

DROP TABLE IF EXISTS site_sales,site_budget;
CREATE TABLE site_sales(ID INT auto_increment primary key, site_id int, busidate date,amt int);

create table site_budget(ID INT auto_increment primary key, site_id int, busidate date,amt int);

insert into site_sales (site_id,busidate,amt) values
(1,'2017-04-01',10),(1,'2017-04-01',20),
(2,'2017-04-01',10);

insert into site_budget (site_id,busidate,amt) values
(1,'2017-04-01',200),
(3,'2017-04-01',100);

此查询

SELECT b.name, 
        sum(case when  a.busidate between '2017-01-01' and '2017-04-30' then a.amt else 0 end) as netamt,
        ifnull((select SUM(CASE WHEN c.busidate BETWEEN '2017-01-01' AND '2017-04-30' THEN c.amt ELSE 0 END) from site_budget c where b.id = c.site_id ),0) as budget
FROM sites b
left JOIN site_sales a ON  b.id = a.site_id 
GROUP BY b.id

结果

+--------+--------+--------+
| name   | netamt | budget |
+--------+--------+--------+
| Store1 |     30 |    200 |
| Store2 |     10 |      0 |
| Store3 |      0 |    100 |
| Store4 |      0 |      0 |
+--------+--------+--------+
4 rows in set (0.00 sec)

如何组合差异表中的2个查询

3 个答案: