Question

你能帮我解决高级SQL查询吗？

我有这样的记录：

id, ProcessName,   Date
 1, Monitor.exe,   2016-05-01 17:00
 2, Monitor.exe,   2016-05-01 17:58
 3, Monitor.exe,   2016-06-11 15:43
 4, Monitor.exe,   2016-05-10 17:24
 5, Monitor2.exe,  2016-06-01 16:01
 6, Monitor2.exe,  2016-06-11 19:05
 7, Keeper.exe,    2016-06-01 13:02
 8, Keeper.exe,    2016-06-14 17:07
 9, Keeper.exe,    2016-06-14 11:00

任务是显示按进程名称分组的最近两个月的记录，并按条目计数并按天排序。像：

date,       ProcessName,   count(*)
2016-05-01, Monitor.exe,   2
2016-05-10, Monitor.exe,   1
2016-06-01, Keeper.exe,    1
2016-06-01, Monitor2.exe,  1
2016-06-11, Monitor.exe,   1
2016-06-11, Monitor2.exe,  1
2016-06-14, Keeper.exe,    2

解决！最终查询是：

SELECT DATE_FORMAT(date, '%m-%d') as EventDate, ProcessName, count(*)
    FROM table_name 
WHERE
    date BETWEEN ADDDATE(NOW(), INTERVAL -30 day) AND NOW()
group by EventDate, ProcessName
order by EventDate

谢谢scaisEdge

Answer 1

您可以使用计数和分组

select date(date), ProcessName, count(*)
from my_table 
group by date(date), ProcessName
order by date(date)

Mysql：从表和组中选择两列

1 个答案: