Python / Sqlite3:与GROUP_CONCAT LEFT JOIN

时间:2017-06-25 09:33:22

标签: python sqlite left-join group-concat

我有两张桌子:

Tasks:                     Predecessors:

ID | Task | Team           ID | TaskID | PredecessorID
---+------+------          ---+--------+--------------
1  | A    | 1              1  | 1      | None
2  | B    | 1              2  | 2      | 1 
3  | C    | 2              3  | 3      | 1
4  | D    | 2              4  | 3      | 2
                           5  | 4      | None

我想选择来自第2组的所有任务,并在该表单中为每个以逗号分隔的任务添加前置任务:

ID | Task | Team | Predecessors
---+------+------+-------------
3  | C    | 2    | 1, 2
4  | D    | 2    | None

因此我使用以下SQL-Query:

SELECT Tasks.*, GROUP_CONCAT(Predecessors.PredecessorID)
FROM Tasks LEFT JOIN Predecessors ON Tasks.ID = Predecessors.TaskID 
WHERE Tasks.Team = 2 GROUP BY Predecessors.TaskID

返回:

ID | Task | Team | Predecessors
---+------+------+-------------
3  | C    | 2    | 1, 2

我该怎样做才能获得无值的行?

这是我的测试代码:

# -*- coding: utf-8 -*-

import sqlite3


con = sqlite3.connect('test.db')
cur = con.cursor()

# Drop old tables if they already exits and create new ones. (For testing).
cur.execute("""DROP TABLE IF EXISTS Tasks""")
cur.execute("""DROP TABLE IF EXISTS Predecessors""")

# Create tables.
cur.execute("""CREATE TABLE Tasks (ID INTEGER PRIMARY KEY AUTOINCREMENT, 
               Task TEXT, Team INTEGER)""")
cur.execute("""CREATE TABLE Predecessors (ID INTEGER PRIMARY KEY AUTOINCREMENT,
               TaskID INTEGER, PredecessorID INTEGER)""")

# Insert some values.
sql = """INSERT INTO Tasks (Task, Team) VALUES (?, ?)"""
for task in [('A', 1), ('B', 1), ('C', 2), ('D', 3)]:
    cur.execute(sql, task)

sql = """INSERT INTO Predecessors (TaskID, PredecessorID) VALUES (?, ?)"""
for predecessor in [(1, None), (2, 1), (3, 1), (3, 2), (4, None)]:
    cur.execute(sql, predecessor)

con.commit()

sql = """SELECT Tasks.*, GROUP_CONCAT(Predecessors.PredecessorID)
FROM Tasks LEFT JOIN Predecessors ON Tasks.ID = Predecessors.TaskID 
WHERE Tasks.Team = 2 GROUP BY Predecessors.TaskID"""
cur.execute(sql)
data = cur.fetchall()
print data

con.close()

感谢您的帮助!!

2 个答案:

答案 0 :(得分:2)

问题是GROUP BY Predecessors.TaskID;对于没有匹配的行,所有Predecessors列都为NULL。

只需使用GROUP BY Tasks.ID

答案 1 :(得分:1)

你应该仔细检查你的代码。你的SQL中没有错,你只是写错了测试数据。

your test data[('A', 1), ('B', 1), ('C', 2), ('D', 3)]
and it should be [('A', 1), ('B', 1), ('C', 2), ('D', 2)]