Question

我正在尝试使用ajax和PHP来获取联系表单，但每次都会收到500错误响应。 PHP不是我的强项，我花了好几个小时试图在我的代码中找到错误，因为我知道必须有一个错误。我甚至尝试过麻烦，但他们告诉我这一切都很好。

JS

$(function() {
   // Get the form.
   var form = $('#ajax-contact');
   // Get the response messages div.
   var formMessages = $('#form-messages');

   // Set up an event listener for the contact form.
   $(form).submit(function(event) {
       // Stop the browser from submitting the form.
       event.preventDefault();

       // Serialize the form data.
       var formData = $(form).serialize();

        // Submit the form using AJAX.
        $.ajax({
           type: 'POST',
           url: $(form).attr('action'),
           data: formData
        })
        .done(function(response) {
           // Make sure that the form-messages div has the 'success' class.
           $(formMessages).removeClass('error');
           $(formMessages).addClass('success');

           // Set the message text.
           $(formMessages).text('Message sent. Expect a reply within 24 hours!');

           // Clear the form.
           $('#name').val('');
           $('#email').val('');
           $('#company').val('');
           $('#message').val('');
        })
        .fail(function(data) {
           // Make sure that the formMessages div has the 'error' class.
           $(formMessages).removeClass('success');
           $(formMessages).addClass('error');

           // Set the message text if there's a respone
           if (data.responseText !== '') {
              $(formMessages).text(data.responseText);
           } else {
              $(formMessages).text('Oops! An error occured and your message could not be sent.');
           }
        });
   });
});

PHP

<?php
// Only process POST reqeusts.
if ($_SERVER["REQUEST_METHOD"] == "POST") {
    // Get the form fields and remove whitespace.
    $name = strip_tags(trim($_POST["name"]));
        $name = str_replace(array("\r","\n"),array(" "," "),$name);
    $email = filter_var(trim($_POST["email"]), FILTER_SANITIZE_EMAIL);
    $company = strip_tags(trim($_POST["company"]));
        $company = str_replace(array("\r","\n"),array(" "," "),$company);
    $message = trim($_POST["message"]);

    // Check that data was sent to the mailer.
    if ( empty($name) OR empty($message) OR !filter_var($email, FILTER_VALIDATE_EMAIL)) {
        // Set a 400 (bad request) response code and exit.
        http_response_code(400);
        echo "There was a problem with your submission. Please complete the form and try again.";
        exit;
    }

    // Set the recipient email address.
    $recipient = "jacob@business.co.uk";

    // Set the email subject.
    $subject = "New message from $name";

    // Build the email content.
    $email_content = "Name: $name\n";
    $email_content .= "Email: $email\n";
    $email_content .= "Company: $company\n\n";
    $email_content .= "Message:\n$message\n";

    // Build the email headers.
    $email_headers = "From: $name <$email>";

    // Send the email.
    if (mail($recipient, $subject, $email_content, $email_headers)) {
        // Set a 200 (okay) response code.
        http_response_code(200);
        echo "Thank You! Your message has been sent.";
    } else {
        // Set a 500 (internal server error) response code.
        http_response_code(500);
        echo "Something went wrong and your message couldn't be sent.";
    }

} else {
    // Not a POST request, set a 403 (forbidden) response code.
    http_response_code(403);
    echo "There was a problem with your submission, please try again.";
}
?>

Answer 1

在您的代码示例中，您有一行

if (mail($recipient, $subject, $email_content, $email_headers)) {

如果mail返回false，它会跳转到else语句，说明：

// Set a 500 (internal server error) response code.
http_response_code(500);
echo "Something went wrong and your message couldn't be sent.";

我猜你的服务器没有sendmail设置。

如果您有权访问和/或使用var_dump（或xdebug，如果您知道如何使用它），请尝试阅读服务器日志，并打印出如下所示的参数：

if (mail($recipient, $subject, $email_content, $email_headers)) {
  // ...
}
else {
    var_dump( error_get_last() );
    var_dump( $recipient );
    var_dump( $subject );
    var_dump( $email_content );
    var_dump( $email_headers );
}

使用PHP mail（）的联系表单响应500错误

1 个答案: