Question

我正在尝试列入Answers＆gt;列; 8和另一列＆lt; 8来自同一领域的答案。[答案（＃）]。字段答案。[答案（＃）]是1-10级的调查结果。我得到错误＆＃34;表达式中不能有聚合函数（IIf（答案。[答案（＃）]＆gt; 8，总和（计数（答案。[答案（＃）]）），＆＃34;＆＃ 34））＆＃34;

在iif函数中，如果我取出sum（查询将分别计算9s和10s，同样适用于8和8以下的数字。我需要在1行中聚合在一起。

SELECT Questions.Year, Questions.[Question Text],
IIf(Answers.[Answer (#)] >8, sum(count(Answers.[Answer (#)])),"") AS Promotors, 
IIf(Answers.[Answer (#)]<=8, sum(Count(Answers.[Answer (#)])),"") AS Detractors
FROM Answers INNER JOIN Questions 
ON Answers.QuestionID = Questions.[Access ID]
WHERE (((Questions.[Question Text]) Like '*Recommend*')) 
and questions.[Question Text] not like '*Are there other technology         services*'
GROUP BY Questions.Year, Questions.[Question Text], Answers.[Answer (#)];

Answer 1

我认为你想要条件聚合。像这样：

SELECT Questions.Year, Questions.[Question Text],
       SUM(IIf(Answers.[Answer (#)] > 8, 1, 0) AS Promotors, 
       SUM(IIf(Answers.[Answer (#)] <= 8, 1, 0) AS Detractors
FROM Answers INNER JOIN
     Questions 
     ON Answers.QuestionID = Questions.[Access ID]
WHERE Questions.[Question Text]) Like '*Recommend*' AND
      questions.[Question Text] not like '*Are there other technology         services*'
GROUP BY Questions.Year, Questions.[Question Text];

您无法嵌套聚合函数。您希望条件作为函数的参数，而不是结果。我还从group by删除了答案列。

访问查询：iif函数错误

1 个答案: