Question

这是我的代码：

＆＃13;

var str = 'http://localhost/myweb/login/resend_password?destination=http://localhost%2Fmyweb%2Fsearch%3Fs%3Dislamic_sources%26q%3D%25D8%25B3%25D9%2584%25D8%25A7%25D9%2585';

var res = str.replace('/(destination=)[^$|&]+/', '$1newval');

console.log(res);

＆＃13;

虽然这是预期的结果：

http://localhost/myweb/login/resend_password?destination=newval

为什么替换在我的代码中不起作用？注意到它适用于this fiddle。

Answer 1

您应该使用：

var str = 'http://localhost/myweb/login/resend_password?destination=http://localhost%2Fmyweb%2Fsearch%3Fs%3Dislamic_sources%26q%3D%25D8%25B3%25D9%2584%25D8%25A7%25D9%2585';

var res = str.replace(/(destination=)[^&]*/, '$1newval');

console.log(res);

正则表达式不应该在引号中，正则表达式需要一些修复，因为[^$|&]+没有做你认为它正在做的事情。

[^$|&]+匹配任何非$而非|而非&

的字符

而不只是非&个字符。

Answer 2

将reg表达式放在没有＆＃39;像这样

＆＃13;

var str = 'http://localhost/myweb/login/resend_password?destination=http://localhost%2Fmyweb%2Fsearch%3Fs%3Dislamic_sources%26q%3D%25D8%25B3%25D9%2584%25D8%25A7%25D9%2585';

var res = str.replace(/(destination=)[^$|&]+/, '$1newval');

console.log(res);

＆＃13;

Answer 3

以下解决方案有效 `

var str = 'http://localhost/myweb/login/resend_password?destination=http://localhost%2Fmyweb%2Fsearch%3Fs%3Dislamic_sources%26q%3D%25D8%25B3%25D9%2584%25D8%25A7%25D9%2585';
var regexpr= /(destination=)[^$|&]+/g;
var res = str.replace(regexpr, '$1newval');
console.log(res);

` 你必须删除引号！

如何替换URL参数的值？

3 个答案: