Question

我正在尝试收集日志文件中2个字符之间的所有文本。

示例日志文件文本为：

Conversation with Boris at 6/30/2017 7:26:35 AM on Server(jabber)
(7:26:41 AM) Boris@Boris.com/Server:  I likes cake
This was a Message from Boris to everyone at 2017-06-29 22:35:18.724681 EVE ~~~

我想收集第一个支架和最后一个支架之间的所有文字。

我一直在尝试使用REGEX来做这件事，但我不确定正确的模式。

有人可以帮忙吗？

Answer 1

根据wOxxOm的评论，这个正则表达式似乎可以解决问题：'(?s)\(.*?~+'

以下是如何在PowerShell中使用它的方法：

$Sample = @"
Conversation with Boris at 6/30/2017 7:26:35 AM on Server(jabber)
(7:26:41 AM) Boris@Boris.com/Server:  I likes cake
This was a Message from Boris to everyone at 2017-06-29 22:35:18.724681 EVE ~~~
"@

$Sample -Match '(?s)\(.*?~+' | Out-Null

$Result = $Matches.Values

此处$Result：

(jabber)
(7:26:41 AM) Boris@Boris.com/Server:  I likes cake
This was a Message from Boris to everyone at 2017-06-29 22:35:18.724681 EVE ~~~

Answer 2

如果您的要求是如此固定，以至于第一次＆＃39;（＆＃39;以及最后＆＃39;〜＆＃39;，我会在不使用Regex的情况下为您提供更简单的解决方案。请查看它< / p>

$x='Conversation with Boris at 6/30/2017 7:26:35 AM on Server(jabber)
(7:26:41 AM) Boris@Boris.com/Server:  I likes cake
This was a Message from Boris to everyone at 2017-06-29 22:35:18.724681 EVE ~~~'

$x.Substring($x.IndexOf('('),$x.IndexOf('~~~')-$x.IndexOf('(')+3)


 #Output
    (jabber)
    (7:26:41 AM) Boris@Boris.com/Server:  I likes cake
    This was a Message from Boris to everyone at 2017-06-29 22:35:18.724681 EVE ~~~

希望这有帮助

在Powershell中获取2个字符之间的所有文本

2 个答案: