Question

我试图在这里创建一个assertTesting函数，它将实际值和期望值与严格相等（不是类型转换）进行比较。

作为一个例子，这是一个成功案例：

function multiplyByTwo(n) {
  return n * 2;
}
var output = multiplyByTwo(2); // returns 4
assertTesting(output, 4, 'it doubles 2 to 4');
// console output:
// passed

这是一个失败的人：

function multiplyByTwo(n) {
  return (n * 2) + 1; // an incorrect implementation
}
var output = multiplyByTwo(2); // returns 5
assertTesting(output, 4, 'it doubles 2 to 4');
// console output:
// FAILED [it doubles 2 to 4] Expected "4", but got "5"

到目前为止，这是我的代码：

var output;

function multiplyByTwo(n) {
  output = n * 2;
  return output;
}

function assertTesting (actual, expected, testName) {
  if(actual === ouput && expected === testName){
    return "SUCCESS" + [testname] + "Expected" + expected + "," "but got" + actual;
  }
}

任何想法如何才能获得我需要的确切输出？请帮忙。

Answer 1

应该是这样的，我想：

function assertEqual(actual, expected, testName) {
  if(actual !== expected){
    console.error( "FAIL [" + testname + "] Expected \"" + expected + ", \" but got \"" + actual + "\"");
  } else {
    console.info( "SUCCESS [" + testname + "]");
  }
}

assertTesting功能成功或失败测试

1 个答案: