PHP MySQL插入具有不同ID的多行

时间:2017-07-05 14:12:48

标签: php mysql

我有下表:

id | message_id | recevier_id
 1 |      8     |    2
 2 |      9     |    5
 3 |     14     |    4

我将数据发送到PHP文件以添加到上表中。我的数据如下:

messageid =“2” 接收者id =“5,6,34”

我正在尝试添加具有不同“接收者ID”的多行,因此上述查询的结果应该导致:

id | message_id | recevier_id
 1 |      8     |    2
 2 |      9     |    5
 3 |     14     |    4
 4 |      2     |    5
 5 |      2     |    6
 6 |      2     |   34

我当前的MySQL查询如下所示:

<?php
$inputvalues = $_POST;
$errors = false;
$result = false;
session_start();
include_once '../../../includes/database.php';
$uid = $_SESSION['usr_id'];
$sendername = $_SESSION['firstnames'].' '.$_SESSION['surname'];

    if (mysqli_connect_errno()) {
        printf("Connect failed: %s\n", mysqli_connect_error());
        exit();
    }

    foreach ($inputvalues as $key => $value) {
        if(isset($value) && !empty($value)) {
            $inputvalues[$key] = $mysqli->real_escape_string( $value );
        } else {
            $errors[$key] = 'The field '.$key.' is empty';
        }
    }

    if( !$errors ) {
        $mysqli->query("
            INSERT INTO `message_receiver_map` (`message_id`, `receiver_id`) VALUES ('".$messageid."', '".$inputvalues['receiverid']."');
        ");
        $returnResult = "Success";
    }
    mysqli_close($mysqli);
    echo json_encode(['result' => $returnResult, 'errors' => $errors]);
    exit;
?>

我怎样才能做到这一点?

2 个答案:

答案 0 :(得分:1)

您可以这样做:

$messageid = "2";         // received value
$receiverids = "5,6,34";  // received value
$receiverid = "";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);

// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}

// prepare and bind
$stmt = $conn->prepare("INSERT INTO `table` (`message_id`, `receiver_id`) VALUES (?, ?)");
$stmt->bind_param("ss", $messageid, $receiverid);

foreach($rid in explode($receiverids)) {
   // set parameters and execute
   $receiverid = $rid;
   $stmt->execute();
}

$stmt->close();

答案 1 :(得分:0)

假设$ _POST中存在2个名为

的字段
$_POST['messageid'] = "2" 
$_POST['receiver id'] = "5,6,34"

然后可以像这样创建3行

请记住,一旦准备好带参数的查询,它就可以重复使用任意次,每次执行时都会有新的参数值。

<?php
    session_start();
    include_once '../../../includes/database.php';

    // this if should probably be in your database.php script
    if (mysqli_connect_errno()) {
        printf("Connect failed: %s\n", mysqli_connect_error());
        exit();
    }

    if ( isset($_POST['messageid'],$_POST['receiver id']) ){ 
        // proceed to create the new rows

        //create a query
        $sql = "INSERT INTO `message_receiver_map` 
                        (`message_id`, `receiver_id`) 
                VALUES (?,?)";

        // prepare the query (send to server and compile it)
        // now this query can be run multiple times with different 
        // parameter set each time it is executed
        $stmt = $mysqli->prepare($sql);

        // now for each receiver_id run the query
        $rec_ids = explode($_POST['receiver id']);

        foreach ($rec_ids as $rec_id) {
            // bind the 2 parameters from this iteration to the query
            $stmt->bind_value('ii', 
                                $_POST['messageid'],
                                $rec_id);
            // run query with these new params
            $result = $stmt->execute();
        }
    }
}
?>

如果你正在使用INNODB数据库,你也可以围绕这个包装一个事务,这样你就可以创建所有3行,或者如果在创建3个新行时某处发生错误则根本没有。

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