Question

在下面的代码中我有两个jsons，我必须根据json数据/值过滤json。

杰森大师：

    var set1 =[{"LevelID":"1","levelname":"Level1",,"levelType":"TypeA"},
    {"LevelID":"2","levelname":"Level2",,"levelType":"TypeB"},
    {"LevelID":"3","levelname":"Level3",,"levelType":"TypeC"},
    {"LevelID":"4","levelname":"Level4",,"levelType":"TypeD"}
    ];

Data Json：

    var set2 =[{"LevelID":"1"},{"LevelID":"2"}];

    var Commaseparated="TypeA","TypeD";

这里我想将Data json和commaseparated传递给Master json并过滤并获取应该与levelID和Commaseparated匹配的过滤数据。

预期结果：

    var set3 =[{"LevelID":"1","levelname":"Level1","levelType":"TypeA"}];

Answer 1

可能不是最好的方式，但这是你开始朝这个方向前进的一种方式。

＆＃13;

var master = [{"LevelID":"1","levelname":"Level1","levelType":"TypeA"},
    {"LevelID":"2","levelname":"Level2","levelType":"TypeB"},
    {"LevelID":"3","levelname":"Level3","levelType":"TypeC"},
    {"LevelID":"4","levelname":"Level4","levelType":"TypeD"}
    ];

var set2 = [{
  "LevelID": "1"
}, {
  "LevelID": "2"
}];

var Commaseparated = ["TypeA", "TypeD"];

const set3 = master.filter(item => {
  return set2.find(item2 => item.LevelID === item2.LevelID)
}).filter(exclude => Commaseparated.indexOf(exclude.levelType) > -1);

/*
const set3 = set2.map(item => {
  item.levelname = Commaseparated[item.LevelID - 1];
  return item;
});
*/

console.log(set3);

＆＃13;

过滤json数据

1 个答案: