我有以下查询：
select username as User, floor((count(Goals)/2)-(if(sum(Loss)>0,1,0))) as Round, sum(Win) as Wins, sum(Goals) as Goals, sum(Loss) as Losses, campaign, Season, ((floor((count(Goals)/2)-(if(sum(Loss)>0,1,0)))*100000)+(sum(Win)*100)+sum(Goals)) as Score from
(select u.username as username, s.campaignno as campaign, if(f.hometeamscore>f.awayteamscore,1,0) as Win, if(f.hometeamscore<f.awayteamscore,1,0) as Loss, f.hometeamscore as Goals, ss.seasonid as Season from straightred_fixture f, straightred_userselection s, auth_user u, straightred_season ss where s.fixtureid = f.fixtureid and s.teamselectionid = f.hometeamid and s.user_id = u.id union all
select u.username as username, s.campaignno as campaign, if(f.awayteamscore>f.hometeamscore,1,0) as Win, if(f.awayteamscore<f.hometeamscore,1,0) as Loss, f.awayteamscore as Goals, ss.seasonid as Season from straightred_fixture f, straightred_userselection s, auth_user u, straightred_season ss where s.fixtureid = f.fixtureid and s.teamselectionid = f.awayteamid and s.user_id = u.id) t
group by username, campaign, Season
having Season = 1025
order by Round DESC, Wins DESC, Goals DESC;
返回以下结果：
+----------------------+-------+------+-------+--------+-----------+--------+--------+
| User | Round | Wins | Goals | Losses | campaign | Season | Score |
+----------------------+-------+------+-------+--------+-----------+--------+--------+
| shanu | 9 | 12 | 36 | 1 | 354102525 | 1025 | 901236 |
| snookro | 7 | 10 | 28 | 2 | 358102528 | 1025 | 701028 |
| tingeypa | 6 | 9 | 19 | 2 | 35910257 | 1025 | 600919 |
| shaun | 5 | 9 | 30 | 1 | 372102520 | 1025 | 500930 |
| shanu | 5 | 9 | 25 | 2 | 35410256 | 1025 | 500925 |
| snookro | 4 | 9 | 26 | 1 | 358102518 | 1025 | 400926 |
| chrakers | 4 | 8 | 26 | 2 | 378102531 | 1025 | 400826 |
| freebet | 4 | 8 | 24 | 1 | 375102524 | 1025 | 400824 |
结果表是正确的，但我只想要最大的＆＃34;分数＆＃34;为每个＆＃34;用户＆＃34;。你可以看到＆＃34; shanu＆＃34;和＆＃34; snookro＆＃34;表中有两个条目。
我试图用max函数包装得分，但MySQL告诉我＆＃34;无效使用组功能＆＃34;。
感谢任何帮助。