Question

所以，首先，我是初学者，在学校有6个月的C＃经验。我可以用另一种方式做到这一点，但我想知道更多的方法来做事情所以.. 我需要帮助。发生的事情是，当我运行程序时一切正常，直到private void Add（），出现一些错误并说Simplify为null？提前谢谢。

using System;

namespace test1
{
 class Details
 {
    int NumberSimplify;
    double Solution;

    private void Ask()
    {
        Console.Write("Would you like to Add or Substract (1 - Add, 2 - Substract) -► ");
        int Opt = int.Parse(Console.ReadLine());

        switch(Opt)
        {
            case 1:
                Console.Write("\nHow many numbers would you like to add? -► ");
                NumberSimplify = int.Parse(Console.ReadLine());                    
                break;

            case 2:
                break;
        }
    }

    public void DisplayResult(double[] Simplify)
    {
        Console.Write("Result from Addition -► ", Add(Simplify));
    }

    private void AddDetails()
    {
        Ask();
        double[] Simplify = new double[NumberSimplify];
        Console.WriteLine();
        for (int i = 0; i < Simplify.Length; i++)
        {
            Console.Write("Number {0} -► ", i + 1);
            Simplify[i] = double.Parse(Console.ReadLine());
        }
    }



    private double Add(double[] Simplify)
    {
        AddDetails();
        for (int i = 0; i < Simplify.Length; i++)
        {
            Solution = Simplify[i] + Simplify[i + 1];
        }
        return Solution;
    }


}


class Execute
{
    public static double[] Simplify { get; private set; }

    static void Main(string[] args)
    {

        Details AddOrSub = new Details();
        AddOrSub.DisplayResult(Simplify);
        Console.ReadLine();

    }
}

}

Answer 1

简化确实是空的....

public static double[] Simplify { get; private set; }

你需要初始化数组......所以这应该更像;

public static double[] Simplify { get; private set; } = new double[someNumberOfElements]

但正如评论中指出的那样，你甚至不使用这个变量的初始版本（无论如何都会在你的下一个方法中被覆盖），所以考虑完全删除它并重新访问你的控制流......

返回简化为null

1 个答案: