$ _FILES [“image”] [“tmp_name”]是没有数据的

Question

我写了以下代码。但是我的空$_FILES[“image”][“tmp_name”]没有价值。

腓：

if ($_FILES) {
$imageFileType = strtolower(pathinfo("img/" . basename($_FILES["Image"]["name"]), PATHINFO_EXTENSION));

$target_file = "img/" . uniqid(rand()) . ".$imageFileType";
if (move_uploaded_file($_FILES["Image"]["tmp_name"], $target_file)) {
   $pic = $target_file;    
} else {

    echo "Invalid File";
    }
}

HTML：

<form action="product-add.php" method="post" enctype="multipart/form-data">
        <div class="products-form">
            <p> Image:</p> <input type="file" name="Image" >   
            <input type="submit" value="ADD PRODUCT" class="btn">
        </div>
</form>

Answer 1

在我看来，这是不对的：

$target_file = "img/" . uniqid(rand()) . ".$imageFileType";

应该是

$target_file = "img/" . uniqid(rand()) . "." .$imageFileType;