Question

def die():
    first = str(randint(1, 6))
    second = str(randint(1, 6))
    total = first + second
    print "You have rolled a " + first + " and a " + second + ", for a total score of " + total + "."

标准掷骰子游戏，但我努力打印个人骰子以及总数的价值。作为个人的字符串处理，但总和导致连接而不是实际的总和。

由于

Answer 1

将变量保留为数字，让print进行格式化：

def die():
    first = randint(1, 6)
    second = randint(1, 6)
    total = first + second
    print "You have rolled a", first, "and a", second, ", for a total score of", total, "."

或者你可以使用str.format进行一些格式化，以便更好地控制上面的默认参数间距：

print "You have rolled a {} and a {}, for a \
total score of {}.".format(first, second, total)

Answer 2

有两种方法可以解决您的问题（还有更多！）。首先，在将它们一起添加时，需要确保将整数保持为类型int，然后在打印出它们时将它们转换为字符串。

您可以使用str()投射方法和+连接来执行以下操作。

def die1():
    """Roll and print two dice using concat."""
    first = randint(1, 6) # keep these as integers
    second = randint(1, 6)
    total = first + second # so addition works
    # but now cast to str when printing
    print "You have rolled a " + str(first) + " and a " + str(second) + ", for a total score of " + str(total) + "."

但更方便的方法是使用str.format()方法将占位符放在字符串中，然后让python为您整理和格式化整数值。如果您有4位或更多位数的大数字，这样做的一个优点是您可以使用字符串格式代码（如"my big number: {0:d,}".format(1000000)）来使您的字符串输出像"my big number: 1,000,000"，这样更易读。< / p>

def die2():
    """Roll and print two dice using str.format()."""
    first = randint(1, 6)
    second = randint(1, 6)
    total = first + second
    # or use the str.format() method, which does this for you
    print "You have rolled a {0} and a {1}, for a total score of {3}.".format(first, second, total)

Answer 3

您可以使用强制转换来更改var的结构。您可以将它们用作字符串并完全使用此行：

 total = int(first) + int(second)

或者将它们用作int并使用str（first）和str（second）将它们转换为print中的字符串

最佳

Answer 4

print "You have rolled a " + str(first) 这会将int转换为字符串，从而将其连接起来。

另外，你可以这样做 total = int(first) + int(second)解决第一个问题。

Answer 5

您有两种解决方案：

在添加数字前将数字转换回int：

def die():
    first = str(randint(1, 6))
    second = str(randint(1, 6))
    total = str(int(first) + int(second))
    print ("You have rolled a " + first + " and a " + second + ", for a total score of " + total + ".")

在打印前将数字转换为str：

def die():
    first = randint(1, 6)
    second = randint(1, 6)
    total = first + second
    print ("You have rolled a " + str(first) + " and a " + str(second) + ", for a total score of " + str(total) + ".")

任何一种解决方案都可以完美地运行。

Answer 6

这也可行。不要将first和second转换为str，直到您对它们执行求和为止。然后记得在str声明中将它们投射为print。

def die():
    first = randint(1, 6)
    second = randint(1, 6)
    total = str(first + second)
    print ("You have rolled a " + str(first) + " and a " + str(second) + ", for a total score of " + total + ".")

如何将var视为int和string。

6 个答案: